Answer:
<em>Value</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em> </em><em> </em><em>-35</em>
Step-by-step explanation:
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
so the basic formula for this d = rt
where d is the distance , r is the speed and t
is time
3800 – 120t = 520 + 40t ( this is the altitude
of each plane are equal)
Solve for t
T = 20.5 min time it takes for the planes to be
at the same altitude
3800 – 120(20.5) = 1340 ft
<span> </span>
Answer: The value of x is 2
Step-by-step explanation:
I just subtracted from both sides and you get 2 and another way to say this is 5-3 and 3-3
Answer:
48 mph
Step-by-step explanation:
First we need to find the distance from Elkhart to Chicago. Toledo to Elkhart is 136 miles and Toledo to Chicago 244 miles.
So the distance from Elkhart to Chicago can be calculated, since Chicago is farther from Toledo than Elkhart, as: distance(Toledo to Chicago) - distance(Toledo to Elkhart). These distances are given in the problem, so the distance from Elkhat to Chicago is: 244 miles - 136 miles = 108 miles.
This problem basically wants to know the slowest you can be yet still ariving on time. If you are the minimum speed, you will arrive in Chicago exactly at 10:30 A.M. So you have 2 hours and 15 minutes(10:30 A.M - 8.15A.M.) to drive 108 miles.
15 minutes is a fourth of a hour, so you have 2.25hours to go through 108 miles.
The minimum speed you must maintain is 108mph/2.25h = 48mph.
Answer:
I'm not sure if you mean each person has a car for 2 weeks and travels 500 miles each but if so the rental cost is $2,940.
If it is just one car for all 3 people the rental cost is $980
Step-by-step explanation:
renatl cost = r
weeks = w
miles = m
the equation would be r = $240w + $1m
and if there are 3 people you mulitply the answer by 3
