Boron:atomic number-5,valency-+3,atomic mass- 11amu
-delta H symbolises an exothermic reaction. Hence, it gives off heat. Reversely, it would absorb heat.
The question is simply asking to convert from units of mass to units of moles. To do this, a conversion factor is needed. For this case, we use the molar mass of glucose which is equal to 180.18 g/mol. We do as follows:
134 g C6H12O6 ( 1 mol / 180.18 g ) = 0.744 mol <span>C6H12O6</span>
Answer:
AlN₃O₉
Explanation:
Assume that you have 100 g of the compound.
Then you have 12.7 g Al, 19.7 g N, and 67.6 g O.
1. Calculate the <em>moles</em> of each atom
Moles of Al = 12.7 × 1/26.98 = 0.4707 mol Al
Moles of N = 19.7 × 1/14.01 = 1.406 mol N
Moles of O = 67.6 × 1/16.00 = 4.225 mol O
2. Calculate the <em>molar ratios</em>.
Al: 0.4707/0.4707 = 1
N: 1.406/0.4707 = 2.987
O: 4.225/0.4707 = 8.976
3. Determine the <em>empirical formula</em>
Round off all numbers to the closest integer.
Al: 1
N: 3
O: 9
The empirical formula is AlN₃O₉.
This depends in what type reaction is occurring. It may be an endothermic reaction or an exothermic reaction. If the reaction is endothermic or heat is being absorbed by the reaction, then the forward reaction is favored or the products are being formed by the addition of heat. If the reaction is exothermic or heat is released by the reaction, then the backward reaction is favored or the reactants are being formed by the addition of heat.