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4 years ago

What is the number of moles of glucose C6H12O6 in a 134g sample?

1 answer:

5 0

The question is simply asking to convert from units of mass to units of moles. To do this, a conversion factor is needed. For this case, we use the molar mass of glucose which is equal to 180.18 g/mol. We do as follows:

134 g C6H12O6 ( 1 mol / 180.18 g ) = 0.744 mol C6H12O6

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Please help me with this I’ll give you extra credit it’s due in 10 minutes thank youuu!!! :))

polet [3.4K]

Answer:

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3 0

3 years ago

The empirical formula for a compound is CH2. Its molar mass is 140.1 g/mol. What is its molecular formula?

ki77a [65]

The empirical formula CH₂ has a mass [(12 × 1) + (1 × 2)] = 14 g/mol

If the empirical formula is 14 g/mol,
and the molecular formula is ~140 g/mol

Then the multiple is = 140 g/mol ÷ 14 g/mol
= 10

Therefor the molecular formula is 10(CH₂) = C₁₀H₂₀

3 0

3 years ago

Read 2 more answers

2. Cuando se añade ácido clorhídrico sobre cinc se produce hidrógeno y cloruro de cinc. Suponiendo

aniked [119]

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3 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = $R=\frac{8.24 mL}{t}$

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = $R'=\frac{3.86 mL}{t}$

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{R}{R'}=\sqrt{\frac{M}{32 g/mol}}$

$\frac{\frac{8.24 mL}{t}}{\frac{3.86 mL}{t}}=\sqrt{\frac{M}{32 g/mol}}$

$M=\frac{32 g/mol\times 8.24 \times 8.24}{3.86\times 3.86}=145.82 g/mol$

4 0

3 years ago

How can the hemlock woolly upset natural ecosystem?

ale4655 [162]

Answer:

The HWA attacks eastern hemlock trees in forests and ornamental hemlock trees found in our residential landscaping. It feeds on the hemlock trees' young twigs by sucking the sap, causing their buds to die and needles to dry out and drop from the plant prematurely i think

hope i helped!!

7 0

3 years ago