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Sladkaya [172]
3 years ago
8

I need help with my last two questions:)

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
6 0

Answer:

5. (a)

6. (b)

I am hoping that this will help you

You might be interested in
The 300 students at a school voted on four possibilities for an end-of-the-year event. The results are shown in the graph below.
fenix001 [56]

Step-by-step explanation:

44-18=26

if 300=100 percent

? =26 percent

26×300=7800

7800÷100=78

the answer is 78 students

5 0
3 years ago
Which strategy would you choose to expand (x+11)(2x+3) and write an equivalent expression
Vlad1618 [11]

Answer:

Step-by-step explanation:

Given the expression (x+11)(2x+3)

We want to expand it and write equivalent expression

Generally if we want to expand an expression we will take one of the expression in one bracket and multiply with the other bracket and then take the other expression and multiply it with the other

E.g, (a+b) × (c + d)

Then, we take a × (c+d) and also b × (c+d)

We can do it the other way round too and it will give the same results.

So, applying this to the given expression

(x+11)(2x+3)

x(2x+3) + 11(2x+3)

2x² + 3x + 22x + 33

2x² + 25x + 33

Then, the equivalent expression is 2x² + 25x + 33

(x + 11)(2x + 3) = 2x² + 25x + 33

5 0
3 years ago
Which transformation represents a reflection over the y-axis?
11111nata11111 [884]

Answer:

1

Step-by-step explanation:

over Y would make the x negative

6 0
3 years ago
Read 2 more answers
If
inna [77]

Answer:

i can only show exaples hope these helps

Step-by-step explanation:

One-to-one

Suppose f : A ! B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c 2 A with

a 6= c, we are guaranteed that f(a) 6= f(c).

Example. f : R ! R where f(x) = x2 is not one-to-one because 3 6= 3

and yet f(3) = f(3) since f(3) and f(3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(x) in more than one point,

then f(x) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate – for example, (2, 3) and

(4, 3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two di↵erent objects in the domain to the same object

of the target.

If every horizontal line in R2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : R ! R where f(x) = x2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

90

Inverse Functions

One-to-one

Suppose f : A ⇥ B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c ⇤ A with

a ⌅= c, we are guaranteed that f(a) ⌅= f(c).

Example. f : R ⇥ R where f(x) = x2 is not one-to-one because 3 ⌅= 3

and yet f(3) = f(3) since f(3) and f(3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(x) in more than one point,

then f(x) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate – for example, (2, 3) and

(4, 3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two dierent objects in the domain to the same object

of the target.

If every horizontal line in R2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : R ⇥ R where f(x) = x2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

66

Inverse Functions

One-to-one

Suppose f : A —* B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c e A with

a ~ c, we are guaranteed that f(a) $ f(c).

Example. f : IR —* JR where f(x) = x2 is not one-to-one because 3 ~ —3

and yet f(3) = f(—3) since f(3) and f(—3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(.x) in more than one point,

then f(z) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate — for example, (2,3) and

(4,3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two different objects in the domain to the same object

of the target.

If every horizontal line in JR2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : JR —, R where f(z) = z2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

\~. )L2

66

Below is the graph of g : R ! R where g(x) = x3. Any horizontal line that

could be drawn would intersect the graph of g in at most one point, so g is

one-to-one.

Onto

Suppose f : A ! B is a function. We call f onto if the range of f equals

8 0
3 years ago
How many degrees are in 3/4 of a full tern
max2010maxim [7]

Answer:

Words: three-quarter turn degree: 270° Revolutions: 3/4

Step-by-step explanation:

If this helps you your welcome and if it doesn’t well that what my teachers taught me

5 0
3 years ago
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