All categories

3 years ago

Please solve with steps

Mathematics

2 answers:

Arada [10]3 years ago

7 0

.......................

Darina [25.2K]3 years ago

5 0

Answer:

x=9

Step-by-step explanation:

isolate the variable by dividing each side by factors that contain the variable

You might be interested in

what is the probability that a card picked at random from a 52-card deck of playing cards is a club or a jack?

ASHA 777 [7]

$|\Omega|=52\\ |A|=\underbrace{13}_{\text{clubs}}+\underbrace{4}_{\text{jacks}}-\underbrace{1}_{\text{jack of clubs}}=16\\\\ P(A)=\dfrac{16}{52}=\dfrac{4}{13}\approx31\%$

7 0

3 years ago

Read 2 more answers

List 3 rational numbers between 3 and 3.9

antiseptic1488 [7]

Answer:

its not showing up

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write the equation in slope-intercept form of a line with slope -2 that passes through the point (1.-7)

tiny-mole [99]

Answer:

y=-2x-5

Step-by-step explanation:

y-y1=m(x-x1)

y-(-7)=-2(x-1)

y+7=-2x+2

y=-2x+2-7

y=-2x-5

6 0

3 years ago

Write an equation in point slope form for the line that passes through (-5,6) and (-3,-9).

Finger [1]

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\qquad
(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-9})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-9-6}{-3-(-5)}\implies \cfrac{-9-6}{-3+5}\implies -\cfrac{15}{2}$

$\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-6=-\cfrac{15}{2}[x-(-5)]\implies y-6=-\cfrac{15}{2}(x+5)
\\\\\\
y-6=-\cfrac{15}{2}x-\cfrac{75}{2}\implies y=-\cfrac{15}{2}x-\cfrac{75}{2}-6\implies y=-\cfrac{15}{2}x-\cfrac{87}{2}$

8 0

3 years ago

Use the model to solve for x.

Vitek1552 [10]

Answer:No solution
Explanation: There is no solution because x was eliminated in the last step of solving for x. Since we were left with x not being available to equal three, it shows it’s a no solution problem. Hope this helped!

4 0

2 years ago