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2 years ago

Pharoah Company had the following adjusted trial balance.

Mathematics

1 answer:

Scrat [10]2 years ago

4 0

Answer:

The solution is given below

Step-by-step explanation:

The preparation of the post closing trial balance is given below

Particulars Debit amount Credit amount

Cash $3,820

Account receivable $4,040

Supplies $490

Account payable $1,800

Unearned service revenue $180

Owner capital ($4,180 + $5,990 - $1,500 - $390 - $1,700 - $770) $5,810

Salary and wages payable $560

Total $8,350 $8,350

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2I + 2w = 48
9 feet is the answer.
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2 years ago

Round 5,836,197 to the nearest humdred

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3 years ago

Read 2 more answers

What is x? if u can’t see it the 2 other degrees are 32 and 120

Westkost [7]

Answer:28

Step-by-step explanation:

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2 years ago

Steve said it does not matter which term is first and which term is second in a ratio, since ratios are different than fractions

marishachu [46]

Ratio is a comparison of two values or two quantities.

Fraction is a another form of ratio.

The first term and the second term in the ratios are important.

It should not be changed.

The first quantity value is in first term and the second quantity value is in second term of the ratio.

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3 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

2 years ago