Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
They are both the second choices 1.)Transitive Property
2.)Reflective Property
PEMDAS so (9+15)= 24 , 24/3 = 8 , 8+2 = 10
Answer:
Step-by-step explanation:
A. 1.13 and B is 1.37
Answer:
g(x) = 
Step-by-step explanation:
The graph is shifted 3 units to the right which is represented by -3 (in the parentheses) and is shifted four units down.
