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agasfer [191]
3 years ago
15

What is the complete factorization of x^4-17x^2+16?

Mathematics
2 answers:
pentagon [3]3 years ago
7 0

Answer:

(x+4)(x-4)(x+1)(x-1)

Step-by-step explanation:

lys-0071 [83]3 years ago
5 0

Answer:

(x +1) (x-1) (x +4) (x-4)

Step-by-step explanation:

The factorization of x^4-17x^2+16 is

(x+1) (x-1) (x+4) (x-4)

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Use the quadratic f(x)=x²+3x-4 and use any method to solve for the Zeros. Use the same function to solve for x when y is 6. F(x)
Katyanochek1 [597]

Answer:

a) f(x) = (x+4)\cdot (x-3), b) x = -5 or x = 2, c) x \approx 2.531 or x \approx -5.531

Step-by-step explanation:

a) The function is solved by factorization:

f(x) = (x+4)\cdot (x-3)

b) The function has the following form:

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The roots of the polynomial are found by factorization:

(x+5)\cdot (x-2) = 0

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c) The function has the following form:

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The roots of the polynomial are determined by the General Formula for the Second-Order Polynomial:

x_{1} = \frac{-3+\sqrt{3^{2}-4\cdot (1)\cdot (-14)}}{2\cdot (1)}

x_{1} \approx 2.531

x_{2} = \frac{-3-\sqrt{3^{2}-4\cdot (1)\cdot (-14)}}{2\cdot (1)}

x_{2} \approx -5.531

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Answer:

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Step-by-step explanation:

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