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agasfer [191]
3 years ago
15

What is the complete factorization of x^4-17x^2+16?

Mathematics
2 answers:
pentagon [3]3 years ago
7 0

Answer:

(x+4)(x-4)(x+1)(x-1)

Step-by-step explanation:

lys-0071 [83]3 years ago
5 0

Answer:

(x +1) (x-1) (x +4) (x-4)

Step-by-step explanation:

The factorization of x^4-17x^2+16 is

(x+1) (x-1) (x+4) (x-4)

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Answer:

  x ≠ 3

Step-by-step explanation:

In any case, the domain is restricted to values of the variable for which the function is defined. The value 1/0 is not defined, so the variable cannot allow the denominator to be zero. The denominator x-3 will be zero for x=3, so that value of the variable cannot be in the domain.

The domain is all real numbers except x=3.

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<em>Additional comments</em>

It is useful to become familiar with the domains of different functions. As we saw above, the reciprocal of 0 is undefined. The square root of a negative number is undefined. The log of a non-positive number is undefined. Trig functions are defined everywhere, but their inverse functions are not. Polynomial functions are defined everywhere, but ratios of polynomials have the same restriction on denominators that we see above.

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Step-by-step explanation:


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3 years ago
Question 2 (Essay Worth 10 points)
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Part A: 1 solution

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Step-by-step explanation:

First you <u>distribute 3(2x-7)=3</u> to 6x-21=3. Next you do inverse operations by <u>adding 21 to both sides</u> of the equation to get 6x=24. Finally you <u>divide both sides by 6</u> to get x=4

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