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denpristay [2]
3 years ago
9

The quiz scores of a group of students in Ms. Evans' math class are shown in the bar graph below.

Mathematics
2 answers:
Alinara [238K]3 years ago
7 0

Answer:

26

Step-by-step explanation:

Nataliya [291]3 years ago
4 0
The answer should be 26 according to my calculations
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I'll. ark brainlyest and give a lot of points for answering this right ​
valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

  • \displaystyle T( - 2,4)
  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

6 0
3 years ago
Which of the following choices describe the bases of a cylinder
shtirl [24]
You have not provided the choices, therefore, I cannot give exact answers.
However, I will try to help you out with some information.

A cylinder is a three-dimensional geometric solid.
It has the same shape as a soda can.

<u>As for the bases, they have the following properties:</u>
1- the bases have a circular (disc) shape
2- the bases are congruent to each other
3- the bases are parallel to each other

Hope this helps :)


8 0
3 years ago
Read 2 more answers
What expression is equivalent to <br> 14<br> −<br> 17<br> ?
DENIUS [597]

answer:

32

Step-by-step explanation:

4 0
3 years ago
Y varies directly as X. If X=2 and y=10. Find Y when X=7
ser-zykov [4K]

Answer:

y= 35

Step-by-step explanation:

y directly proportional to x

where x= 2, y= 10

y=kx

10= k× 2

k= 10/2

k= 5

to find y when x is 7

y = kx

y = 5× 7

y= 35

6 0
2 years ago
What is the exact value of cos (67.5°)?
babymother [125]

first off, make sure you have a Unit Circle, if you don't do get one, you'll need it, you can find many online.

let's double up 67.5°, that way we can use the half-angle identity for the cosine of it, so hmmm twice 67.5 is simply 135°, keeping in mind that 135° is really 90° + 45°, and that whilst 135° is on the 2nd Quadrant and its cosine is negative 67.5° is on the 1st Quadrant where cosine is positive, so

cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\\\ cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos(135^o)\implies cos(90^o+45^o)\implies cos(90^o)cos(45^o)~~ - ~~sin(90^o)sin(45^o) \\\\\\ \left( 0 \right)\left( \cfrac{\sqrt{2}}{2} \right)~~ - ~~\left( 1\right)\left( \cfrac{\sqrt{2}}{2} \right)\implies -\cfrac{\sqrt{2}}{2} \\\\[-0.35em] ~\dotfill

cos(67.5^o)\implies cos\left( \frac{135^o}{2} \right)\implies \pm \sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}\implies \stackrel{I~Quadrant}{+\sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}} \\\\\\ \sqrt{\cfrac{ ~~ \frac{2-\sqrt{2}}{2} ~~ }{2}}\implies \sqrt{\cfrac{2-\sqrt{2}}{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{\sqrt{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{2}

8 0
2 years ago
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