Answer:
see explanation
Step-by-step explanation:
To determine which ordered pairs are solutions to the equation
Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.
(- 1, - 6)
3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution
(- 3, 3)
3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution
(11, 3)
3(11) - 4(3) = 33 - 12 = 21 = right side ← thus a solution
(7, 0)
3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution
The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation
Answer:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
Step-by-step explanation:
We have these following probabilities:
An 88% probability that the day is cloudy.
An 54% probability that the day is both foggy and cloudy.
What is the probability that a randomly selected day in November will be foggy if it is cloudy?
This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
Answer:
1.96 planes
Step-by-step explanation:
The computation of the number of planes is shown below:
As we know that
System Inventory is
= Flow rate in the system × Throughput time
where,
Flow rate is
= Frequency of taken off
= 16 planes ÷ hour
= 16 ÷ 60 Planes per minute
Throughput time is
= runway waiting time + runway Run time
= 33 seconds + 6 minutes × 60 seconds + 48 seconds
= 441 seconds
= 441 per 60 seconds
Therefore the number of planes is

= 1.96 planes
Answer:
31
Step-by-step explanation: