Graphing the circle and the points shows that the point that lies outside the circle is ...
(2, 0)
S.A = (2×area of base) + area of lateral faces
Area of lateral faces = area of base × height
Area of lateral faces = 19×4×8=608
S.A = (2×19×4)+608
=760
Answer:
21.9°
Step-by-step explanation:
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
We solve this above question using the Sine rule
a/sin A = b/sin B
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.
Hence:
HI/∠J = JH/∠H
= 8/sin 90° = 1.9/sin ∠H
Cross Multiply
∠H = arc sin(sin 1.9 × 90/8)
∠H = 21.9°
Answer:
[-1, 6)
General Formulas and Concepts:
<u>Algebra I</u>
- Reading a coordinate plane
<u>Algebra II</u>
- Range is the set of y-values that are outputted by function f(x)
- Interval Notation - [Brackets] denote inclusion and (Parenthesis) denote exclusion
Step-by-step explanation:
According to the graph, our y-values span from -1 to 6. Since -1 is a closed dot, it is inclusive. Since 6 is an open dot, it is exclusive:
Range would then be [-1, 6).
Answer:
The division will be represented as:
Step-by-step explanation:
1) Let's find a number with a variable that multiplied by 6x gives as 18x². It will be 3x, because (6x+5)3x=18x²+15x.
Now, let's subtstract:
2) Let's find a number with a variable that multiplied by 6x gives as -18x. It will be -3, because (6x+5)(-3)=-18x-15.
Now, let's subtstract:
Therefore, the division will be represented as:
I hope it helps you!
