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Diano4ka-milaya [45]

2 years ago

9

Anitra has 12 hair ribbons. One fourth of the ribbons are pink. Three are purple, and the rest are red. What fraction of Anitra'

s hair ribbons is red?

1 answer:

Hatshy [7]2 years ago

6 0

Pink ribbons are 3 ( 12:4)
3 pink + 3 purple =6 (together)
12-6 = 6(red)
Fraction is 6/12 simplify 1/2 the answer is one half (1/2)

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The cost of a book was decreased from 60 to 50 by what percent the price decrased with solution

Artist 52 [7]

Answer:

The price decreased by 16 1/3%, or approximately 16.3%

Step-by-step explanation:

Use the formula for percent change. If the answer is negative, it is a percent decrease. if the answer is positive, it is a percent increase.

percent change = (new price - old price)/(old price) * 100%

In this case, use:

new price = 50

old price = 60

percent change = (new price - old price)/(old price) * 100%

percent change = (50 - 60)/60 * 100%

percent change = -10/60 * 100%

percent change = -1/6 * 100%

percent change = -100/6% = -50/3% = -16 1/3%

The price decreased by 16 1/3%, or approximately 16.3%

7 0

3 years ago

HELP asap pls, first right=brainliest

Sergeeva-Olga [200]

Answer:

Your answer would be A:12

Step-by-step explanation:

4 0

2 years ago

What graph represents the function f(x)= -x2+5?

ololo11 [35]

I hope it would helps

6 0

3 years ago

A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d

Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

$P(A) = P_{1} + P_{2} + P_{3}$

In which $P_{1}$ is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

$P_{1} = 0.35*0.25 = 0.0875$

$P_{2}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{2} = 0.15*0.05 = 0.0075$

$P_{3}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{3} = 0.50*0.15 = 0.075$

So

$P(A) = 0.0875 + 0.0075 + 0.075 = 0.17$

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

$P = \frac{0.5*0.15}{0.17} = 0.4412$

There is a 44.12% probability that the defective product came from C.

3 0

3 years ago

An election ballot asks voters to se4five city commissioners from a group of fifteen candidates. In how many wsys can this be do

svp [43]

That's "15 choose 5"

$\displaystyle{15 \choose 5} = \dfrac{15! }{5! 10!} = \dfrac{15 \cdot 14 \cdot 13 \cdot 12 \cdot 11}{5 \cdot 4 \cdot 3 \cdot 2 \cdot 1} = (15/(5(3))(14/2)(13)(12/4)(11)\\\\= 7(13)(3)(11)=231(13)=3003$

Answer: 3003 ways

8 0

3 years ago