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Diano4ka-milaya [45]
3 years ago
9

Anitra has 12 hair ribbons. One fourth of the ribbons are pink. Three are purple, and the rest are red. What fraction of Anitra'

s hair ribbons is red?
Mathematics
1 answer:
Hatshy [7]3 years ago
6 0
Pink ribbons are 3 ( 12:4)
3 pink + 3 purple =6 (together)
12-6 = 6(red)
Fraction is 6/12 simplify 1/2 the answer is one half (1/2)
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Two swimmers start out from opposite ends of a swimming pool(red side and blue side). They cross each other for the first time a
daser333 [38]

Answer:

13 yds

Step-by-step explanation:

the blue side starter (B) swims 29yd in the time it takes the red side starter (R) to swim 21yd

their combined distance, when they meet, is 50yd (length of pool)

 

they pass each other and continue to the ends of the pool (combined distance, 100yd)

they swim towards each other again, and pass a second time (combined distance, 150yd)

at this point, R has swum 63yd (3*21) -- one length plus 13yd

so RS is 13yd from the blue end

7 0
4 years ago
"6. A brand name has a 40% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small s
statuscvo [17]

Answer:

(a) The probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b) The probability that all of the selected consumers recognize the brand name is 0.0041.

(c) The probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d) The events of 5 customers recognizing the brand name is unusual.

Step-by-step explanation:

Let <em>X</em> = number of consumer's who recognize the brand.

The probability of the random variable <em>X</em> is, P (X) = <em>p</em> = 0.40.

A random sample of size, <em>n</em> = 6 consumers are selected.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the value of P (X = 5) as follows:

P(X=5)={6\choose 5}0.40^{5}(1-0.40)^{6-5}\\=6\times0.01024\times0.60\\=0.036864\\\approx0.0369

Thus, the probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b)

Compute the value of P (X = 6) as follows:

P(X=6)={6\choose 6}0.40^{6}(1-0.40)^{6-6}\\=1\times 0.004096\times1\\=0.004096\\\approx0.0041

Thus, the probability that all of the selected consumers recognize the brand name is 0.0041.

(c)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = P (X = 5) + P (X = 6)

              = 0.0369 + 0.0041

              = 0.041

Thus, the probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d)

An event is considered unusual if the probability of its occurrence is less than 0.05.

The probability of 5 customers recognizing the brand name is 0.0369.

This probability value is less than 0.05.

Thus, the events of 5 customers recognizing the brand name is unusual.

8 0
4 years ago
2400 people attended a football game. If 4% of the people who attended were teenagers, how many teenagers attended the game?
jonny [76]
96
2400*.04
96
you are welcome
6 0
3 years ago
Plz help! Due tonight!
Alecsey [184]

the answer will be

48$ dollars

7 0
3 years ago
Read 2 more answers
Can someone help me with #3? Thanks!
labwork [276]
I hope this helps you

4 0
3 years ago
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