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Alla [95]
3 years ago
5

Suppose a bank charges a base rate of $5 plus $0.10 per check for your checking account. You can switch to a different account t

hat charges $4 plus $0.20 per check. For what number of checks is the monthly cost of the two accounts the same? What is the cost?
Mathematics
1 answer:
wolverine [178]3 years ago
8 0

Answer:

10 number of checks.

Cost = $6

Step-by-step explanation:

Given that:

Fixed Charges of first bank = $5

Charges of first bank per check = $0.10

Fixed Charges of second bank = $4

Charges of second bank per check = $0.20

To find:

Number of checks such that the charges for the banks become the same?

Solution:

Let the number of checks = x

Cost for the first bank for x checks = $5 + $0.10x

Cost for the second bank for x checks = $4 + $0.20x

As per question statement, both the costs are the same.

Comparing the values:

5 + 0.10x = 4 + 0.20x\\\Rightarrow 0.10x = 1\\\Rightarrow x = 10

So, for 10 number of checks the cost will be same.

The cost = 4 + 0.20 \times 10 = <em>$6</em>

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Solnce55 [7]

Answer:

5 to the 15th power.

Step-by-step explanation:

PEMDAS requires us to do parenthesis, then exponents, and then division. Let's do 5³. 5x5x5 is equal to 125. Now, we find 125 to the ninth power. According to my calculations, 125 to the ninth power is equal to 7,450,580,596,923,828,125. Now, we find 5 to the twelfth power, which, according to my calculations, is 244,140,625. Now, we solve. According to my calculations, 7,450,580,596,923,828,125/244,140,625 is equal to 30,517,578,125. 30,517,578,125 is equivalent to 5 to the 15th power. That means that the second option is correct. I hope this helps!

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3 years ago
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azamat

Answer:

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8 0
3 years ago
A company is replacing cables with fiber optic lines in rectangular casing BCDE. If segment DE = 3 cm and segment BE = 3.5 cm, w
Simora [160]

Answer: 3.66 cm

Step-by-step explanation: Given a rectangular casing BCDE with segment DE = 3 cm and segment BE = 3.5 cm.

The area A of a rectangle is length multiply by width.

Where length L = 3.5 cm and

width W = 3 cm

Area A = 3.5 × 3 = 10.5 cm^2

The pipe that will fit the fiber optic line is in cylindrical shape. Where area of a cylinder = πr^2.

But area A = 10.5. Substitute the values for the area of the cylinder

10.5 = πr^2

10.5 = 3.143 × r^2

Make r^2 the subject of formula

r^2 = 10.5/3.143

r = sqrt ( 3.34225 )

r = 1.828

Diameter = 2 × radius

Diameter = 2 × 1.829

Diameter = 3.656 cm

Therefore, the smallest diameter of pipe that will fit the fiber optic line is 3.66 cm approximately.

8 0
4 years ago
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MakcuM [25]

Answer: f(x) = 195 - x*5

Step-by-step explanation:

Colton has 120 small prizes and 75 larger prizes.

Then at the start, he has 120 + 75 = 195 prizes.

In each bag, he puts 3 small prizes and 2 larger prizes, then in each bag there are 3 + 2 = 5 prizes.

Then if he fills x bags, he will have: x*5 fewer prizes, then we can write the equation f(x) as:

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Where when x = 0, this means that he filled zero bags, then he has the initial amount of prizes, 195.

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3 years ago
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liberstina [14]

Answer:

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