All categories

3 years ago

(need help asap)

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

7 0

Step-by-step explanation:

give more points then I will tell

You might be interested in

Can someone please help, I need this done soon :))

Sonja [21]

The volume of the pyramid is $726 \mathrm\ {cm}^{3}$

Explanation:

The height of the square pyramid is 18 cm

The base of the square pyramid is 11 cm

The volume of the square pyramid can be determined using the formula,

$V=\frac{1}{3} b^{2} h$

Substituting $b=11$ and $h=18$ in the formula, we have,

$V=\frac{1}{3} (11)^{2} (18)$

Simplifying, we have,

$V=\frac{1}{3} (121)(18)$

Multiplying, we get,

$V=\frac{2178}{3}$

Dividing, we get,

$V=726 \ cm^3$

Thus, the volume of the pyramid is $726 \mathrm\ {cm}^{3}$

5 0

3 years ago

PLEASE HELP ASAP! MARKING BRAINLIEST!! Only do the first column. PLease please don't put anything silly, i give out points all t

USPshnik [31]

Answer:

This was posted a long time ago Sorry I'm super late!

Step-by-step explanation:

I assume you already completed this question but I am trying to move up a level and have full points yet still need more brainliest so I was hoping you could still mark me brainliest? Its fine if not no worries. Have an amazing day and a spectacular spring break!

Please mark brainliest!

Remember your worth! Have a great day and year!

8 0

2 years ago

X^2 + 32x + 256 = 1<br>please show steps

Elena L [17]

$\boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$

<h2>Explanation:</h2>

In this case, we have the following equation:

$x^2+32x+256=1$

But we can write this equation as:

$x^2+32x+256=1 \\ \\ Subtract \ -1 \ from\ both \ sides: \\ \\ x^2+32x+256-1=1-1 \\ \\ x^2+32x+255=0$

So this final result is a quadratic equation written in Standard Form ( $ax^2+bx+c=0$ ). We need to find the solutions to this equations, so let's use quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ b=32 \\ c=255 \\ \\ \\ x=\frac{-32 \pm \sqrt{(32)^2-4(1)(255)}}{2(1)} \\ \\ x=\frac{-32 \pm \sqrt{1024-1020}}{2} \\ \\ x=\frac{-32 \pm \sqrt{4}}{2} \\ \\ x=\frac{-32 \pm 2}{2} \\ \\ Finally, \ two \ solutions: \\ \\ \boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$