Answer:
Translate 
up 
units and shade inside the V
Step-by-step explanation:
we know that
The function has the vertex at point 
The function 
has the vertex at point 
so
the rule of the translation is
That means
The translation is units up
The solution of the inequality 
is the shaded area inside the V
see the attached figure to better understand the problem
therefore
the answer is
Translate up units and shade inside the V
Well, for
her questionnaire she could use and create questions or queries that are
obviously related to her hypothesis or study.
These
could be done in a likert type of scale.
<span><span>
1.
</span>I read most often.
</span>
<span><span>a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
<span><span>
2.
</span>When I read my books its takes me 24 hours a day</span>
<span><span>
a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
<span><span>
3.
</span>When I start reading I can’t stop</span>
<span><span>
a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
Answer:
It only counts as a zero when the y-intercept is (0,0).
Step-by-step explanation:
The zeros of a quadratic function are always written as (x,0), while the y-intercept is always written as (0,y). Therefore, in order for a y-intercept to be a zero, it must be (0,0), because the y-coordinate in any zero is 0. At any other time, the y-intercept is not a zero.
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
???????
Step-by-step explanation:
