Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
Step-by-step explanation:
Given that;
p = 10% = 0.1
so let q = 1 - p = 1 - 0.1 = 0.9
n = 818
μ = np = 818 × 0.1 = 81.8
α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58
Now to find P( x < 100)
we say;
Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12
P(x<100) = P(z < 2.12)
from z-score table
P(z < 2.12) = 0.9830
Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830
The first one x is greater than and equal to 34
Answer: 1.645
Step-by-step explanation:
Given : The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variabilities in the amount of soda in the company's 16 OZ bottles is more than the variabilities in the company's 12 OZ bottles.
Let 
represents the variance for 16 OZ bottles and 
represents the variance for 12 OZ bottles.
The Null and Alternative Hypothesis will be :-
, since alternative hypothesis is left-tailed , then the test is left-tailed test.
By using the standard normal distribution table for z, the critical value for this hypothesis:-
Answer:
-2.25
Step-by-step explanation:
Since there are 4 ticks between 2 numbers, we do 1/4 = 0.25
Now we find the value:
-2.25
