Ask question

Ask question

All categories

3 years ago

7

Someone help me on this before i decide to drop out

1 answer:

valkas [14]3 years ago

5 0

The only thing you need to do is 'cross-multiply'

Take the top of fraction 1 and multiply it to the bottom of fraction 2, and take the bottom of fraction 1 and multiply it to the top of fraction 2.

Then you will get a nice and easy equation to solve!

You might be interested in

What is 6/3 of 2/3 please answer

Cerrena [4.2K]

Answer:

1.33 or 4/3

Step-by-step explanation:

6/3 ×2/3

2/3× 2/1

= 4/3

=1.33

6 0

3 years ago

Addison has a balance of $3,450 on her credit card that has an APR of 18%. She currently pays the minimum monthly payment of $86

malfutka [58]

Answer:

Addison can eliminate $45 from Food/Clothes and $41 from Entertainment.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find all critical numbers of the function <img src="https://tex.z-dn.net/?f=g%28x%29%3Dx%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7D-2x%5E%

postnew [5]

Differentiate g using the power rule:

$g'(x) = \dfrac34 x^{\frac34-1} - 2\cdot\dfrac14 x^{\frac14-1}$

$g'(x) = \dfrac34 x^{-\frac14} - \dfrac12 x^{-\frac34}$

$g'(x) = \dfrac14 x^{-\frac34} \left(3 x^{\frac12} - 2\right)$

$g'(x) = \dfrac{3\sqrt x - 2}{4 x^{\frac34}}$

The critical points of g occur where g' is zero or undefined.

We have

$g'(x) = 0 \implies 3\sqrt x - 2 = 0 \implies \sqrt x = \dfrac23 \implies \boxed{x = \dfrac49}$

and the derivative is undefined for

$\dfrac1{g'(x)} = 0 \implies 4x^{\frac34} = 0 \implies \boxed{x=0}$

8 0

3 years ago

There were 7 carnations for sale in the store there was four times as many roses as carnations

jekas [21]

If you multiply 7 * 4 it will give you the number of carnations which is 28.

4 0

3 years ago

*One half of two fifths of x.

Nataly_w [17]

Answer:

one half of two fifths of x would be equivalent to one fifth of x

3 0

3 years ago