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den301095 [7]
4 years ago
13

William has a regular hexagon with sides that are 2 units each. How many equilateral triangles with 1- unit sides can be put tog

ether to make the hexagon?
Mathematics
1 answer:
Alina [70]4 years ago
7 0
In a regular hexagon, each side is contained in a separate equilateral triangle with side of 2-units.  That makes six equilateral triangles with side 2-units.
Further, each equilateral triangle of side 2-units contains four (4) equilateral triangles of side 1-unit.
Therefore the total number of equilateral triangles of side 1 units in a hexagon with side two units is 6*4=24.
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Nimfa-mama [501]
Yes, the table is correct
There would be 60 squares as the ratio of triangles to squares is 3:4
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3 years ago
makayla has $8 to buy at a school fair each ticket cost $1.50 which inequality best represents how many tickets she can buy
ivolga24 [154]

Answer:

Step-by-step explanation:

If she only has $8, she can't spend more than that.  In other words, she can spend ≤$8.

If each ticket is $1.50 per ticket, the inequality that represents how many tickets she can buy if x represents the number of tickets, is

1.5x ≤ 8

6 0
3 years ago
Solve each equation mentally.
larisa [96]

Answer:

1) 1/17

2) 1/111

3) 1/15

They're all fractions

Hope that helped, just divide the result with the number available

Example :

1÷17 =1/17

4 0
3 years ago
Which of the following equations vould u solve by first adding six. and divided by -3
Reil [10]
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6 0
3 years ago
Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
4 years ago
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