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2 years ago

Jack needs 22 pirates for every 2 pirate ships he manages

Mathematics

1 answer:

dimulka [17.4K]2 years ago

3 0

So does he have two pirate ships? that would be 22*2=44

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(1) Tom took a trip of 1,020 miles. He traveled by train at 55 miles an hour and the same number of hours by plane at 285 mph.

Maurinko [17]

<h3>Answer:</h3>

B) 6 hours

<h3>Step-by-step explanation:</h3>

Let h represent the total trip time. Then h/2 is the time spent traveling at each speed. The distance covered is ...

... distance = speed · time

The sum of the distances in each mode is the total distance.

... 1020 = 55·h/2 +285·h/2

... 2040 = h·(55+285) . . . . multiply by 2

... 2040/340 = h = 6 . . . . . . . divide by the coefficient of h

The trip took a total of 6 hours.

4 0

2 years ago

Help pls i need help !!

Ivanshal [37]

Answer:

Ray, Line, Transversal?, Plane, Segment

Step-by-step explanation:

6 0

2 years ago

The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5

vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score, $\bar x$ =3.5

Score(x) frequency C.F

1 1 1

2 3 4

3 f 15(4+f=4+11)

4 13 28

5 4 32

$\sum f_i=1+3+f+13+4=21+f$

$\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f$

$(\bar x)=\frac{\sum f_ix_i}{\sum f_i}$

Using the formula

$3.5=\frac{79+3f}{21+f}$

$73.5+3.5f=79+3f$

$3.5f-3f=79-73.5$

$0.5f=5.5$

$f=\frac{5.5}{0.5}=11$

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

$Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}$

Median= $\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4$

7 0

3 years ago

What is the half way point of -20 and +10

Zolol [24]

Answer:

the answers is -5

Step-by-step explanation:

-20 -15 -10 -5. 0 +5. +10

6 0

3 years ago

Read 2 more answers

Find the volume of each figure

pshichka [43]

Answer:

See explanation

Step-by-step explanation:

1. The first figure shows triangular prism. The volume of the triangular prism is

$V=\text{Base area}\times \text{Height}$

The base of this triangular prism is the triangle with the base of 7 cm and height of $h$ cm (it is not seen).

The base area is

$\text{Base area}=\dfrac{1}{2}\times \text{Base}\times \text{Height}=\dfrac{1}{2}\times 7\times h=\dfrac{7h}{2}\ cm^2$

and the volume of the prism is

$V=\dfrac{7h}{2}\times 13=\dfrac{91h}{2}\ cm^3$

Just substitute the length of the height and calculate the volume.

2. The second figure shows square pyramid. The volume of the square pyramid is

$V=\dfrac{1}{3}\times \text{Base area}\times \text{Height}$

The base of this square pyramid is the square with the side length of 4 yd.

The base area is

$\text{Base area}= \text{Side Lenght}^2=4^2 =16\ yd^2$

and the volume of the pyramid is

$V=\dfrac{1}{3}\times 16\times 12=64\ yd^3$

7 0

2 years ago