Answer:
the answer is c so hope this helps you best of the luck
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
A and D
Explanation: I did this problem in khan academy
Answer:
hx-h2+6
Step-by-step explanation:
First solve the parentheses, do h*x - 2h, then add the +6.
Hope I helped! :D
Answer:
for q 19 its x=209ft and for 21 its 66.5 ft i forgot q 20
Step-by-step explanation:
