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Travka [436]
3 years ago
14

PLEASE HELP ITA DUE AT 9​

Mathematics
2 answers:
bekas [8.4K]3 years ago
5 0
B is the correct answer
PSYCHO15rus [73]3 years ago
4 0

Answer:

its the third one

Step-by-step explanation:

1.7x10^9

take care

-tired kitten

who wants to rest forever

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a car rents for $40 per day plus 21 cents per mile. you are on a daily budget of $82. what mileage will allow you to stay within
pav-90 [236]

Answer:

200 miles will allow to stay within the budget

Step-by-step explanation:

∵ The daily budget is 82

∵ The cost per mile is 21/100 = $0.21

∵ The number of miles is x

∴ The equation of the budget is:

∴ 82 = 40 + 0.21 x

∴ 0.21 x = 82 - 40

∴ 0.21 x = 42

∴ x = 42/0.21 =200

∴ The number of miles = 200 to stay in the daily budget

3 0
3 years ago
Find its inverse and check your answer. (b) Find the domain and the range of f and
ElenaW [278]

We have the function:

f(x) = 3x / (x + 7)

(a)

We rename the function as: f(x) = y

Then:

y = 3x / (x + 7)

Taking the inverse:

1/y = (x + 7) / 3x

1/y = x/3x + 7/3x

1/y = 1/3 + 7/3x

Solving for x:

1/y - 1/3 = 7/3x

1/x = 3/7y - 1/7 = (3 - y) / 7y

Taking the inverse:

x = 7y / (3 - y)

Then, the inverse function of f is:

f ⁻¹(x) = 7x / (3 - x)

(b)

We know that the division by 0 is undefined in real numbers. From the function f, we have a division by 0 if x = -7, so the domain should be:

Dom_f = {x| x ≠ -7}

For the range, we know that x = -7 is a vertical asymptote of the function f, so this means that the graph never passes across x = -7, but it tends to it on infinity. Then, the range of f is:

Ran_f = All the real numbers

For f ⁻¹(x), we see that for x = 3 there is a division by 0, so this is an asymptote of the function. Then, the domain of f ⁻¹ is:

Dom_f ⁻¹ = {x| x ≠ 3}

Again, as there is an asymptote, the range is:

Ran_f ⁻¹ = All the real numbers

7 0
1 year ago
What side length do the area of models of 45 and 60 have in common
Oliga [24]
ABC³√ω⇔\int\limits^a_b {x} \, dx   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] 1233
6 0
3 years ago
Please help me! I need help. Please help me, I need help, please help me!
stiv31 [10]

Answer:

17x

Step-by-step explanation:

3x+4+4x+4+3x-4+3x-4+4x

Collect liketerms

5 0
2 years ago
What term can you add to 5/6x -4 to make an equivalent to 1/2x-4
solmaris [256]

Answer:

Denote adding term = a

a = (5/6x) - 4 - (1/2x) - 4

a = (5/6x) - (1/2x)

a = (5/6x) - (3/6x)

a = (2/6x)

a = (1/3x)

*******************************

a = (5/6)x - 4 - (1/2)x - 4

a = (5/6)x - (1/2)x

a = (5/6 - 1/2)x

a = (1/3)x

Hope this helps!

7 0
3 years ago
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