Nolan is: x- 2, 8, 14, 20 y- 8, 9, 10, 11
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240 children and 382 adult swam at the public pool that day
<em><u>Solution:</u></em>
Let "c" be the number of childrens
Let "a" be the number of adults
Cost of 1 child ticket = $ 1.75
Cost of 1 adult ticket = $ 2.50
<em><u>622 people used the public swimming pool</u></em>
Therefore,
number of childrens + number of adults = 622
c + a = 622 ------ eqn 1
<em><u>The receipts for admission totaled $ 1375.00</u></em>
Therefore, we can frame a equation as:
number of childrens x Cost of 1 child ticket + number of adults x Cost of 1 adult ticket = 1375.00
1.75c + 2.50a = 1375 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
c = 622 - a -------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
1.75(622 - a) + 2.50a = 1375
1088.5 - 1.75a + 2.50a = 1375
0.75a = 1375 - 1088.5
0.75a = 286.5
a = 382
<em><u>Substitute a = 382 in eqn 3</u></em>
c = 622 - 382
c = 240
Thus 240 children and 382 adult swam at the public pool that day
tis always a good idea when factoring to start off with a quick prime factoring.