Work=force*distance
27*3 = 81 joules of energy (required work)
:)
1.) Solving for x: x= -(3y/2) +5
solving for y= -(2x/3)+3 1/3
2.)solving for x: x= 10y/3+5
solving for y: y=3x/10 - 1 1/2
Please make sure to check with classmates for answers, to help each other.
Plug it into the midpoint formula.
x1+x2/2; y1+y2/2
R (-5,4) S (3,2)
-5+3/2; 4+2/2
-2/2; 6/2
(-1,3) or "C"
I hope this helps!
~cupcake
D. All real numbers is the answers
So the first three possible values of g^2 + 3 are:
3, 4, 7
The first option is the correct one.
<h3>
Which ones are the first three possible values?</h3>
The set of the whole numbers is {0, 1, 2, 3...}
Then the first possible value is when g = 0.
0^2 + 3 = 3
The second possible value is when g = 1
1^2 + 3 = 4
The third possible value is when g = 2.
2^2 + 3 = 7
So the first three possible values of g^2 + 3 are:
3, 4, 7
The first option is the correct one.
If you want to learn more about whole numbers:
brainly.com/question/5243429
#SPJ1
