you're answer is 0
If the numerator is 0, then your answer is 0
If the denominator is 0, then your answer is *undefined*
This is because, you can have 0 parts of a whole.
hope this helps
Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer:
option-A
Step-by-step explanation:
we are given
divisor is
Dividend is
=x-2
so, we can use synthetic division
so, we can write our expression as
so,
option-A
Answer:
The answerrrrrrrrrrr is (0,-2)
I believe that the answer is AA similarity (A).
