Answer:
15.21 %
Explanation:
If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:
p + q = 1
p² + 2pq + q² = 1
where;
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p² = percentage of homozygous dominant individuals
q² = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
Given that p= 0.68 and q = 0.39
the percentage of the homozygous recessive genotype (q² ) will be
(0.39)² = 0.1521
= 0.1521 × 100
= 15.21 %
∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %
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Answer:
healing process
Explanation:
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During gametogenesis, if
nondisjunction occurs in meiosis II (meaning that that at least one pair of
sister chromatids did not separate), the resultant effect will be two cells that
has the normal haploid number of chromosomes (n), one cell that has an extra
chromosome (n + 1), and one cell that has one missing chromosome (n - 1). In
summary, two of the gametes will be n, one will be n + 1, one will be n — 1.
<span>Allele frequency is a factor within a population that can be studied in order to determine whether or not a population is evolving. Alleles are one of two or more ways in which a particular gene can be expressed. One can measure this expression in a population and measure its frequency to measure whether or not the population is evolving.</span>