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3 years ago

A human heart beats an average of 80 beats per minute. How many beats is this in an hour?

Mathematics

2 answers:

Aleksandr [31]3 years ago

8 0

Answer:

4800 beats an hour

Step-by-step explanation:

there are 60 minutes in and hour

the heart beats 80 times per minute( that is actually a very high heart rate)

80*60=4800 per hour

grigory [225]3 years ago

7 0

I believe the answer is an average of 4800 beats per hour.
We know that the heart beats an average of 80 beats per minute and there are 60 minutes in an hour. We can use this information and multiply 80x60 to find the average amount of heartbeats in an an hour.

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7x + 4y = 2<br> 7x + 2y = 8

Mariana [72]

Answer:

x = 2 , y = − 3

Step-by-step explanation

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form: ( 2 , − 3 )

Equation Form: x = 2 , y = − 3

3 0

3 years ago

Which of the following is the surface area of the right cylinder below?

Snowcat [4.5K]

Answer: Option A.

Step-by-step explanation:

You need to use this formula for calculate the surface area of the right cylinder:

$SA=2\pi r^2+2\pi rh$

Where "r" is the radius and "h" is the height.

You can identify in the figure that:

$r=8units\\h=3units$

Knowing this, you can substitute these values into the formula $SA=2\pi r^2+2\pi rh$ , therefore you get that the surface area of this right cylinder is:

$SA=2\pi (8units)^2+2\pi (8units)(3units)$

$SA=176\pi\ units^2$

8 0

3 years ago

What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27

malfutka [58]

Answer with explanation:

$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0

3 years ago

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I am stuck on this question of my maths test.

V125BC [204]

Answer:

angle y

58 + 38 + y = 180 (angle sum property)

96 + y = 180

y = 180 - 96

y = 84

angle x

x = 29 (58/2)

(angle subtended by an arc at centre is double the arc at any point on remaining part of centre)

the values of x = 29 and y = 84

6 0

3 years ago

Simplify the expression<br>

KonstantinChe [14]

Answer:

9/4

Step-by-step explanation:

5×|-2-7(3)|-2×17

5×|-2-21|-34

5×|-23|-34

5×23-34

115-34=81

22+sq rt(7×28) 28=4×7 sq rt= 2×2×7×7

22+2×7=22+14=36

81÷9/36÷9=9/4

7 0

3 years ago

Read 2 more answers