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3 years ago

I need work shown help

Mathematics

1 answer:

Kamila [148]3 years ago

8 0

your computer is cracked

Step-by-step explanation:

makes it hard to see here

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How can a kepler-47c happen?? Plz help :(

Natali5045456 [20]

Answer:

I'm not SUPER sure but, it only can exist where there is a region in a planetary system where liquid water might exist on the surface of a planet. That puts it in the "habitable zone" which is where it can exist.

6 0

3 years ago

Find f(-2) for the function: f(x)= 3x^2-1, x<1 x+2, x> 1

azamat

F(x) = 3x² - 1
f(-2) = 3(-2)² - 1
f(-2) = 3(4) - 1
f(-2) = 12 - 1
f(-2) = 11

f(x) = x < 1
f(-2) = -2 < 1

f(x) = x + 2
f(-2) = -2 + 2
f(-2) = 0

f(x) = x > 1
f(-2) = -2 > 1
f(-2) = -2 < 1

8 0

3 years ago

What is the value of k if 7k" minutes past nine" is the same as 8k" minutes to ten"?

schepotkina [342]

Answer:

4 minutes

Step-by-step explanation:

The value of 7k "minutes past nine" is the same as 8k" minutes to ten".

Since there are 60 minutes in an hour and 9 and 10 fall in between the same hour, this means that:

7k = 60 - 8k

7k + 8k = 60

15k = 60

k = 60 / 15

k = 4 minutes

5 0

3 years ago

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

3 years ago

In a number with at least two digits, the last number was removed. The resulting number was n smaller than ghe previous one.

BartSMP [9]

Answer:

The largest possible value of n is 11.

(A) is correct option.

Step-by-step explanation:

Given that,

The number with at least two digits,the last number was removed. The resulting number was n smaller than the previous one.

We need to find the largest possible value of n

Using given data,

The smallest number of two digit is 10.

Now, we removed last digit then we get 1 which is equal to 10 divided 10.

So, n = 10

But the largest number of two digit is 99.

We removed last digit then we get 9 which is equal to 99 divided 11.

So, n = 11

Hence, The largest possible value of n is 11.

(A) is correct option.

5 0

3 years ago