Question in English:
A female carries a recessive lethal gene (l) on one of her X chromosomes, and a normal dominant allele (L) on the other. What is the sex ratio to be expected in this woman's dependency if she marries a normal man?
Answer:
2/3 females
1/3 males
Explanation:
Females have two X chromosomes (XX) and males have an X and a Y chromosome (XY).
The genotype of the female is XLXl. The genotype of the male is XLY, since he is normal.
The possible genotypes are:
<u> XL Xl</u>
<u>XL</u> <em>XLXL XLXl</em>
<u>Y</u> <em>XLY </em><em>XlY</em>
<em />
All female offspring will be normal as they will always have one normal copy of the X chromosome from their father.
50% of the male offspring will be normal, but 50% will inherit the lethal gene from their mother.
Because the allele is lethal, that means XlY males will not be born.
That means 2/3 of the children will be females, and 1/3 will be males.
Mutualism since the clown fish and the anemone both benefit from each other.
Who is Dede and what are her symptoms. We need more context
Answer:
c) Breaks down and inactivates acetylcholine
Explanation:
Acetylcholinesterase is an enzyme that is required for termination of acetylcholine activity in the synaptic cleft. The enzyme is present in the extracellular side of the motor endplate membrane and breaks down the acetylcholine into acetyl and choline.
In the absence of acetylcholine, the muscle fibers resume their resting stage. Therefore, acetylcholinesterase activity is required for the normal functioning of muscles and nerve cells that use acetylcholine as a neurotransmitter.
