2 years ago

A.tell what point is located at each ordered pair

Mathematics

1 answer:

Anna11 [10]2 years ago

5 0

Answer: all of them are x,y

Step-by-step explanation:

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I need to show how to find these solutions 1/4 and 3/4 by completing the square!

Arlecino [84]

Answer:

See explanation, and ask for more details if unclear!

Step-by-step explanation:

The perfect square of this equation is $x^2-x+\frac{1}{4}$ , since the square would be $(x-\frac{1}{2})^2$ . 1/4=4/16, meaning that you can set up the equation in the following way:

$(x^2-x+\frac{1}{4})-\frac{1}{16}=0$

$(x-\frac{1}{2})^2=\frac{1}{16}$

Take the square root of both sides:

$x-\frac{1}{2}=\pm \frac{1}{4}$

Add 1/2 to both sides:

$x=\frac{1}{2}\pm \frac{1}{4}=\frac{3}{4}, \frac{1}{4}$ . Hope this helps!

8 0

2 years ago

Read 2 more answers

Find the value of the lesser root of x 2-8x+7=0

mariarad [96]

Hi there! The answer is x = 1

${x}^{2} - 8x + 7 = 0$

$(x - 7)(x - 1)$
Rule AB = 0, gives A = 0 or B = 0

$x - 7 = 0 \: \: or \: \: x - 1 = 0 \\ x = 7 \: \: \: \: \: \: \: \: \: or \: \: x = 1$
Therefore, the smallest of both roots is x = 1.

7 0

2 years ago

Solve them please, correct answers will be marked as brainliest & a follow :) thank you x<br>

DaniilM [7]

Answer:

this is the answer that I could do please check it if I could help you