10 is not a perfect square I believe
Answer: 1: cant figure out sorry :(
2: 2.5
3: 5
4: 20
5: 25
10: 50
Step-by-step explanation: What i did here was divided by 5 the numbers below 3 and multiply by 5 for the numbers above 3. Hope this helps :)
Answer:

Step-by-step explanation:
The y-intercept (when x = 0) on the quadratic graph is 3, the upper quadratic graph does not intersect the x-axis, and the endpoint of the function has an open circle that stops at x = 1. The starting point extends to the boundaries of the graph
Therefore, the piecewise function shown in the quadratic graph is given as follows;
f(x) = x² + 3; x < 1
The straight line graph has a negative slope and starts at x = 1, with a closed circle, extending to higher values of <em>x</em> to the boundaries of the graph
Two points on the straight line graph are (1, 3) and (5, -5), therefore, the slope is (-5 - 3)/(5 - 1) = -2
The equation of the function is y - 3 = -2·(x - 1)
∴ y = f(x) -2·x + 2 + 3 = -2·x + 5
f(x) = -2·x + 5; x ≥ 1
Answer:
n(-9+ n) =0
Step-by-step explanation:
-9n+n^2=0 Kind of use 'reverse distributive' property
n (-9 + n) = 0
This is most easily done using the expanded form of the expression.
∫(9 -9t +t² -t³)dt = 9t -(9/2)t² +(1/3)t³ -(1/4)t⁴ +c