Answer:
Step-by-step explanation:
Method 1: Taking the log of both sides...
So take the log of both sides...
5^(2x + 1) = 25
log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...
(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...
(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...
(2x)log 5 + log 5 - log 5 = log 25 - log 5
(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)
(2x)log 5 = log 5 <-- divide both sides by log 5
(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..
2x = 1
x=1/2
Method 2
5^(2x+1)=5^2
2x+1=2
2x=1
x=1/2
it would be car d because of what the time was on the chart (i did the test and it was correct)
Answer: a) H = h( 0.5 )^n
b) H = 1.125inches
Step-by-step explanation:
Let H = height of the ball
n = number of time the ball bounces
h = initial height.
The exponential function to model the height of the ball will be:
H = h( 1 - 0.5)^n
H = h( 0.5 )^n
It's minus because the height of the ball is decreasing.
h = 36 inches
n = 5
H = 36( 1 - 0.5 ) ^5
H = 36( 0.5 )^5
H = 36 × 0.03125
H = 1.125inches
Answer:
k = -8
Step-by-step explanation:
-2k+13=-8k-35
Add 8k to each side
-2k+8k+13=-8k+8k-35
6k +13 = -35
Subtract 13 from each side
6k+13-13 = -35-13
6k = -48
Divide by 6
6k/6 = -48/6
k = -8
