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3 years ago

8

Answer fast plz sjsjzjz

2 answers:

Finger [1]3 years ago

7 0

Answer:

104

Step-by-step explanation:

Just separate the whole thing into two shapes. Multiply the first shape: 12 x 7 = 84

Multiply the second shape: 5 x 4 = 20

Mekhanik [1.2K]3 years ago

4 0

104 is the answer hope it helps

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The foul lines of a baseball field intersect at home plate to form a right angle. A batter hits a fair ball such that the path o

liraira [26]

Answer:

The angle formed between the first base foul line and the path of the baseball is 63°.

Step-by-step explanation:

This is not a difficult problem. We only need to remember the measure of a right angle, which is 90°. Now, recall that the path baseball divides the right angle in two angles, and we know the measure of one of them.

In the attached figure the black lines are the foul lines of the baseball field, and the blue line is the baseball path. In green is the given angles and colored red is the wanted angle.

So, the sum of the angles α and β is 90° and we know the measure of the angle α: 27°. So,

α + β = 90° .

Then,

β = 90° - α = 90° - 27° = 63°.

5 0

3 years ago

4. Henry and his brother each start a savings account. Henry begins with $200 and deposits $25 each month. His brother begins wi

bixtya [17]

Answer:

After 5 months they will both have $325 in their savings account

Step-by-step explanation:

200, 225, 250, 275, 300, 325

150, 185, 220, 255, 290, 325

So you can see that they both have the same amount after 5 months

7 0

3 years ago

BRAINLY FOR CORRECT ANSWER

Papessa [141]

Answer:

a

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A video game uses the quadratic equation h equals space minus 16 t to the power of 2 space end exponent plus space 64 t space pl

stellarik [79]

Answer:

Step-by-step explanation:

Given

h varies as

$h=-16t^2+64t+190$

Above h represents the height of object at any instant t

For example at t=0

h=190 ft

At t=1 s

h=-16+64+190=238 ft

For maximum height differentiate h w.r.t time

$\frac{\mathrm{d} h}{\mathrm{d} t}=-16\times 2\times t+64$

Put $\frac{\mathrm{d} h}{\mathrm{d} t}=0$ to get maximum height

$-32t+64=0$

t=2 i.e. at t= 2 s h is maximum

h at t=2 s

$h=-16\times 2^2+64\times 2+190=254 m$

7 0

4 years ago

How do you use the limit comparison test on this particular series?<br>Calculus series tests

barxatty [35]

Compare $\dfrac1{\sqrt{n^2+1}}$ to $\dfrac1{\sqrt{n^2}}=\dfrac1n$ . Then in applying the LCT, we have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac1{\sqrt{n^2+1}}}{\frac1n}\right|=\lim_{n\to\infty}\frac n{\sqrt{n^2+1}}=1$

Because this limit is finite, both

$\displaystyle\sum_{n=1}^\infty\frac1{\sqrt{n^2+1}}$

and

$\displaystyle\sum_{n=1}^\infty\frac1n$

behave the same way. The second series diverges, so

$\displaystyle\sum_{n=0}^\infty\frac1{\sqrt{n^2+1}}=1+\sum_{n=1}^\infty\frac1n$

is divergent.

4 0

4 years ago