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Soloha48 [4]
3 years ago
6

Nuclear Power is a perfect example of exponential relations. Canada produces over half of its electricity using nuclear reactors

. One of the major problems associated with nuclear power generation is the radioactive waste. Currently all nuclear waste is stored on site at the power plant and there is no solution for the long term waste.
A) What would you do with the long term waste?

B) How would you take care of Canada’s energy needs for the future?
Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Solution :

Nuclear fission is exponential. With uranium atoms arranged properly it is possible to have the fission effect and cause more and more uranium nuclei to fission. This is known as chain reaction and a number of uranium atoms are fission together to increase exponentially.

Canada, for example produces electricity using the process of fission process in its nuclear reactors.

But one of the problems with nuclear reactors is its disposal of the nuclear waste. The nuclear waste includes the used reactor fuel,  uranium mill tailings and other radioactive wastes. They remain radioactive and are dangerous for the human health.

A). The long term nuclear waste are stored in deep excavations and covered with rocks and mud so that the harmful radioactive materials does not escape from them. They are also stored in some high density and thick cylinders and remained isolated in the dump yard from the people and nature.

B). Canada has a high source of renewable sources of energy. This is a clean source of energy and Canada can make best use of it. Most of the energy requirement of Canada can be taken care off by using wind energy. Canada is planning to set up wind energy mills in most of its part and generate electricity from it.

Canada has also installed several solar power projects which is clean and can help the people to use this solar energy to produce electricity.

Learn More :

brainly.com/question/1013815  

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Consider the given data. x 0 2 4 6 9 11 12 15 17 19 y 5 6 7 6 9 8 8 10 12 12 Use the least-squares regression to fit a straight
levacccp [35]

Answer:

See below

Step-by-step explanation:

By using the table 1 attached (See Table 1 attached)

We can perform all the calculations to express both, y as a function of x or x as a function of y.

Let's make first the line relating y as a function of x.

<u>y as a function of x </u>

<em>(y=response variable, x=explanatory variable) </em>

\bf y=m_{yx}x+b_{yx}

where

\bf m_{yx} is the slope of the line

\bf b_{yx} is the y-intercept

In this case we use these formulas:

\bf m_{yx}=\frac{(\sum y)(\sum x)^2-(\sum x)(\sum xy)}{n\sum x^2-(\sum x)^2}

\bf b_{yx}=\frac{n\sum xy-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}

n = 10 is the number of observations taken (pairs x,y)

<u>Note:</u> <em>Be careful not to confuse  </em>

\bf \sum x^2 with \bf (\sum x)^2

Performing our calculations we get:

\bf m_{yx}=\frac{(83)(95)^2-(95)(923)}{10*1277-(95)^2}=176.6061

\bf b_{yx}=\frac{10*923-(95)(83)}{10(1277)-(95)^2}=0.3591

So the equation of the line that relates y as a function of x is

<h3>y = 176.6061x + 0.3591 </h3>

In order to compute the standard error \bf S_{yx}, we must use Table 2 (See Table 2 attached) and use the definition

\bf s_{yx}=\sqrt{\frac{(y-y_{est})^2}{n}}

and we have that standard error when y is a function of x is

\bf s_{yx}=\sqrt{\frac{39515985}{10}}=1987.8628

Now, to find the line that relates x as a function of y, we simply switch the roles of x and y in the formulas.  

So now we have:

x as a function of y

(x=response variable, y=explanatory variable)

\bf x=m_{xy}y+b_{xy}

where

\bf m_{xy} is the slope of the line

\bf b_{xy} is the x-intercept

In this case we use these formulas:

\bf m_{xy}=\frac{(\sum x)(\sum y)^2-(\sum y)(\sum xy)}{n\sum y^2-(\sum y)^2}

\bf b_{xy}=\frac{n\sum xy-(\sum x)(\sum y)}{n(\sum y^2)-(\sum y)^2}

n = 10 is the number of observations taken (pairs x,y)

<u>Note:</u> <em>Be careful not to confuse  </em>

\bf \sum y^2 with \bf (\sum y)^2

Remark:<em> </em><em>If you wanted to draw this line in the classical style (the independent variable on the horizontal axis), you would have to swap the axis X and Y) </em>

Computing our values, we get

\bf m_{xy}=\frac{(95)(83)^2-(83)(923)}{10*743-(83)^2}=1068.1072

\bf b_{xy}=\frac{10*923-(95)(83)}{10(743)-(83)^2}=2.4861

and the line that relates x as a function of y is

<h3>x = 1068.1072y + 2.4861 </h3>

To find the standard error \bf S_{xy} we use Table 3 (See Table 3 attached) and the formula

\bf s_{xy}=\sqrt{\frac{(x-x_{est})^2}{n}}

and we have that standard error when y is a function of x is

\bf s_{xy}=\sqrt{\frac{846507757}{10}}=9200.5856

<em>In both cases the correlation coefficient r is the same and it can be computed with the formula: </em>

\bf r=\frac{\sum xy}{\sqrt{(\sum x^2)(\sum y^2)}}

Remark: <em>This formula for r is only true if we assume the correlation is linear. The formula does not hold for other kind of correlations like parabolic, exponential,..., etc. </em>

Computing the correlation coefficient :

\bf r=\frac{923}{\sqrt{(1277)(743)}}=0.9478

5 0
4 years ago
In circle S with m RST = 42 and
ANTONII [103]

Answer:

2.20

Step-by-step explanation:

First, change 42° to radian

42/180 * π = 0.733 rad

The length of the arc = 3 * 0.733 = 2.20

8 0
2 years ago
G(2)<br> +7<br> What is the average rate of change of g over the interval -2.4)
solmaris [256]

Answer:

Rate = 1

Step-by-step explanation:

Given

g(x) = x + 7

Interval: (-2,4)

Required

Determine the average rate of change

This is calculated using:

Rate = \frac{g(b) - g(a)}{b-a}

Where:

(a,b) = (-2,4)

So, we have:

Rate = \frac{g(4) - g(-2)}{4-(-2)}

Rate = \frac{g(4) - g(-2)}{4+2}

Rate = \frac{g(4) - g(-2)}{6}

Calculate g(4) and g(-2)

g(4) = 4 + 7 = 11

g(-2) = -2 + 7 = 5

So:

Rate = \frac{11 - 5}{6}

Rate = \frac{6}{6}

Rate = 1

<em>Hence, the average rate of change is 1</em>

3 0
3 years ago
Please help ASAP, LIKE RIGHT NOWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWW
BlackZzzverrR [31]

Answer:

266yd^2

Step-by-step explanation:

A = b x h

15.2 x 17.5 = 266

4 0
3 years ago
2 less than 1/8 of some number W can be expressed algebraically as
Yuliya22 [10]
The expression would be (w divided by 1/8) - 2
3 0
3 years ago
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