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3 years ago

Describe what sandpaper does to wood to make it smoother, and explain why.

Physics

2 answers:

Rama09 [41]3 years ago

8 0

Answer it scapes away loose anf rough pieces of wood

Explanation:

bazaltina [42]3 years ago

8 0

Answer:

To achieve a nice smooth finish, it's essential to sand to help prepare the area for painting application, by sanding you are removing imperfections (also known as pimples), creating a nice smooth finish while at the same time adding adhesion by developing small, rough ridges for the paint to stick to.

Using the right sandpaper can make all the difference in a woodworking, painting, or finishing project; but choosing between the many different types of sandpaper that are available can be a challenge. Here are some tips on how to choose the best sandpaper for your next project.

Explanation:

Sry if this is wrong :(

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1. A diver jumps from a 13 m tower, with no initial velocity.

Valentin [98]

Answer:

Assuming that air resistance is negligible.

a. Approximately $16.1\; {\rm m\cdot s^{-1}}$ .

b. Approximately $19.0\; {\rm m \cdot s^{-1}}$ .

Explanation:

Let $m$ denote the mass of this diver.

If the initial speed of the diver is $v_{0}$ , the initial kinetic energy ( $\text{KE}$ ) of this diver would be $(1/2)\, m \, {v_{0}}^{2}$ .

If the height of this diver is $h$ , the gravitational potential energy ( $\text{GPE}$ ) of this diver would be $m\, g \, h$ .

The initial mechanical energy of this diver (sum of $\text{KE}$ and $\text{GPE}$ ) would thus be: $(((1/2)\, m\, {v_{0}}^{2}) + (m\, g\, h}))$ .

If air resistance on the diver is negligible, the mechanical energy of this diver would stay the same until right before the diver impacts the water. The entirety of the initial mechanical energy, $(((1/2)\, m\, {v_{0}}^{2}) + (m\, g\, h}))$ , would be converted to kinetic energy by the time of impact.

Rearrange the equation $\text{KE} = (1/2)\, m\, v^{2}$ to find an expression for the speed of the diver:

$\begin{aligned} v = \sqrt{\frac{2\, \text{KE}}{m}}\end{aligned}$ .

Thus, if the kinetic energy of the diver is $(((1/2)\, m\, {v_{0}}^{2}) + (m\, g\, h}))$ , the speed of the diver would be:

$\begin{aligned} v &= \sqrt{\frac{2\, \text{KE}}{m}} \\ &= \sqrt{2\times \frac{(1/2)\, m\, {v_{0}}^{2} + (m\, g\, h)}{m}} \\ &= \sqrt{2 \times ((1/2)\, {v_{0}}^{2}) + (g\, h))} \\ &= \sqrt{{v_{0}}^{2} + 2\, g\, h}\end{aligned}$ .

Notice how $m$ , the mass of the diver was eliminated from the expression.

If the diver started with no initial speed ( $v_{0} = 0\; {\rm m\cdot s^{-1}}$ ) at a height of $h = 13\; {\rm m}$ , the speed of the diver right before impact with water would:

$\begin{aligned} v &= \sqrt{{v_{0}}^{2} + 2\, g\, h} \\ &= \sqrt{{(0\; {\rm m\cdot s^{-1}})}^{2} + (2 \times 10\; {\rm m\cdot s^{-2} \times 13\; {\rm m})} \\ &\approx 16.1\; {\rm m\cdot s^{-1}}\end{aligned}$ .

If the diver started with an initial velocity of $10\; {\rm m\cdot s^{-1}}$ upwards (initial speed $v_{0} = 10\; {\rm m\cdot s^{-1}}$ ) from a height of $h = 13\; {\rm m}$ , the speed of the diver right before impact with water would be:

$\begin{aligned} v &= \sqrt{{v_{0}}^{2} + 2\, g\, h} \\ &= \sqrt{{(10\; {\rm m\cdot s^{-1}})}^{2} + (2 \times 10\; {\rm m\cdot s^{-2} \times 13\; {\rm m})} \\ &\approx 19.0 \; {\rm m\cdot s^{-1}}\end{aligned}$ .

5 0

3 years ago

If a student connects two resistors to a circuit parallel would the total resistance increase, decrease or does it not change an

OverLord2011 [107]

The total resistance would decrease

8 0

4 years ago

A hockey puck is hit so that it leaves the stick at 50.4m/s. If it takes 0.25 s for the puck to hit the boards, how far is the p

notka56 [123]

Speed = 50.4 m/s
Time = 0.25 s

Distance = (speed) x (time) = (50.4 m/s) x (0.25 s) = 12.6 meters.

3 0

3 years ago

A 72 kg sled Is pulled forward from rest by a snowmobile and accelerates at 2 m/s squared forward for five seconds. The force of

Inga [223]

So first make a force diagram. I would label forward forces + and backward forces -. Essentially, the drag force is equal to the Ft (force of tension) + Ff (force of friction on snowmobile - driver system). The force of Friction is equal to mu * Fn. We can find mu through the force of friction acting on the sled. 120 N = mu * Fn (equal to m * g of sled). mu of the Ice is equal to 0.167. So, 540 N = Ft + 0.167 * 4500 N. Ft = -211.5 N. <u>Ft is acting in the backwards direction at a magnitude of 211.5 N</u>

3 0

4 years ago

Is there a way to see the color of cosmic rays the human eye can't see

KATRIN_1 [288]

You would have to use a machine to convert the colors to one visible by humans or become some other species of animal with a larger light spectrum.

4 0

3 years ago