Question

Carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas. If Carlos exerts 2,000 N of force to pull the rope, and the rope is at an angle of 15° to the road, how much work did he do? Round your answer to two significant figures.

Answer 1

Answer: $5.8\cdot 10^4 J$

Explanation:

The work done by Carlos is given by:

$W=Fdcos\theta$

where

F is the force exerted by Carlos

d is the distance through which the car has been pulled

$\theta$ is the angle between the direction of the force and the motion of the car

In this problem, $F=2000 N, d=30 m, \theta=15^{\circ}$. By substituting these numbers into the formula, we find

$W=(2,000 N)(30 m)(cos 15^{\circ})=57,956 J=5.8\cdot 10^4 J$

Answer 2

5.8 × 104 J
i already checked it on edge