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3 years ago

Write and graph the inverse variation in which y = 8 when x = –4.

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

3 0

For this case we have that an inverse variation in a function is given by:
$y = k / x
$
For this case, we must find the value of the constant k.
To do this, we substitute the values of x = -4, y = 8.
We have then:
$8 = k / -4
$
Clearing k we have:
$k = (8) * (- 4)

k = -32$
Substituting the value of k we have that the inverse variation is:
$y = -32 / x
$
Note: see attached image.
Answer:
$y = -32 / x
$
See attached image.

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Flura [38]

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3 years ago

A right triangle has one 64degree angle and one 90 degree angle

melamori03 [73]

Answer:

I dont know what your asking, for the other angle? Ig so. Answer: THE OTHER ANGLE IS 26. :)

Step-by-step explanation:

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3 years ago

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beks73 [17]

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3 years ago

Please provide an answer

Igoryamba

Answer:

Step-by-step explanation:

The opposite angles in a quadrilateral theorem states that when a quadrilateral is inscribed in a circle, the angles that are opposite each other are supplementary, their degree measures add up to 180 degrees. One can apply this here by using the sum of (<C) and (<A) to find the measure of the parameter (z). Then one can substitute in the value of (z) to find the measure of (<B). Finally, one can use the opposite angles in a quadrilateral theorem to find the measure of angle (<D) by using the sum of (<B) and (D).

Use the opposite angles in an inscribed quadrialteral theorem,

<A + <C = 180

Substitute,

14x - 7 + 8z = 180

Simplify,

22z - 7 = 180

Inverse operations,

22z = 187

z = $\frac{187}{22}$

Simplify,

z = $\frac{17}{2}$

Now substitute the value of (z) into the expression given for the measure of angle (<B)

<B = 10z

<B = 10( $\frac{17}{2}$ )

Simplify,

<B = 85

Use the opposite angles in an inscribed quadrilateral theorem to find the measure of (<D)

<B + <D = 180

Substitute,

85 + <D = 180

Inverse operations,

<D = 95

8 0

3 years ago

Read 2 more answers

In a random sample of 8 people, the mean commute time to work was 33.5 minutes and the standard deviation was 7.2 minutes. A 95

Elina [12.6K]

Answer: Margin of error = 6.58

Confidence interval = (26.91, 40.08)

Step-by-step explanation:

Since we have given that

Sample size n = 8

Sample mean = 33.5 minutes

Population standard deviation = 9.5 minutes

At 95% confidence interval,

α = 0.05

t = 1.96

So, Margin of error is given by

$t\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{9.5}{\sqrt{8}}\\\\=6.58$

Confidence interval would be

Lower limit:

$\bar{x}-6.58\\\\=33.5-6.58\\\\=26.91$

Upper limit:

$\bar{x}+6.58\\\\=33.5+6.58\\\\=40.08$

Hence, the interval would be (26.91, 40.08)

But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)

Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.

3 0

3 years ago