Answer:
The mentioned number in the exercise is:
Step-by-step explanation:
To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.
If:
- x = hundredths digit
- y = tens digit
- z = ones digit
We can write:
- x = z + 1 (the hundreds digit is one more than the ones digit).
- y = 2x (the tens digit is twice the hundreds digit).
- x + y + z = 11 (the sum of the digits is 11).
Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:
- x + y + z = 11
- (z + 1) + y + z = 11 (remember x = z + 1)
- z + 1 + y + z = 11
- z + z +y + 1 = 11 (we just ordered the equation)
- 2z + y + 1 = 11 (z + z = 2z)
- 2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
- 2z + y = 10
- 2z + (2x) = 10 (remember y = 2x)
- 2z + 2x = 10
- 2z + 2(z + 1) = 10 (x = z + 1 again)
- 2z + 2z + 2 = 10
- 4z + 2 = 10
- 4z = 10 - 2
- 4z = 8
- z = 8/4
- <u>z = 2</u>
Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:
- x = z + 1
- x = 2 + 1
- <u>x = 3</u>
And we'll use the second equation to obtain the value of y (the tens digit):
- y = 2x
- y = 2(3)
- <u>y = 6</u>
Organizing the digits, we obtain the number:
- Number = xyz
- <u>Number = 362</u>
As you can see, <em><u>the obtained number is 362</u></em>.
Answer:
Factoring the expression
completely we get 
Step-by-step explanation:
We need to factor the expression
completely
We need to find common terms in the expression.
Looking at the expression, we get
is common in both terms, so we can write:

So, taking out the common expression we get: 
Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

So, we get:

Therefor factoring the expression
completely we get 
Answer:
Area of the flying saucer = 
Step-by-step explanation:
The Flying saucer is in the shape of a circle.

Area of the circular flying saucer= 
:
Area= 
Area of the flying saucer 
So, the area of the flying saucer is 
the student needed to place a ten outside the radical, as a perfect square of 100 composes 200. This way, a two should be left under the radical sign. Also, this would be about 14.1 because 14^2 is 196 and 15^2 is 225. The correct answer must be less than 225, more than 196, but closer to 196. Therefore, a .1 is added to the 14
Answer:
=ykvnn
Step-by-step explanation: