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wlad13 [49]
2 years ago
13

What is the difference between arithmetic and relational operators​

Computers and Technology
1 answer:
denpristay [2]2 years ago
4 0

Answer:

The arithmetic operator is used by the program to perform simple algebraic operations like addition, subtraction, multiplication, division, etc. Relational operators are the ones that are used to validate a relationship between the two operands as if they are equal, greater than, less than, etc.

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Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th
Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)    

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

Explanation:  

Unification: Any substitution that makes two expressions equal is called a unifier.  

a) P(B,A,B), P(x,y,z)  

Use { x/B}  

=> P(B,A,B) , P(B,y,z)  

Now use {y/A}  

=> P(B,A,B) , P(B,A,z)  

Now, use {z/B}  

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }  

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q  

c. Older(Father(y),y), Older(Father(x),John)  

Use {y/x}  

=> Older(Father(x),x), Older(Father(x),John)  

Now use { x/John }  

=> Older(Father(John), John), Older(Father(John), John)  

Thus , mgu ={ y/x , x/John }  

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))  

Use { y/x }  

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}  

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B  

e) P(f(x), x, g(x)), P(f(y), A, z)  

Use {x/y}  

=> P(f(y), y, g(y)), P(f(y), A, z)  

Now use {z/g(y)}  

P(f(y), y, g(y)), P(f(y), A, g(y))  

Now use {y/A}  

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

7 0
3 years ago
Which bug type would you suggest for the following bug? The button label "Add to cart" is not fully visible.
harina [27]
Butterfly one I forgot the name metapods evolution
3 0
3 years ago
In a C++ program, one and two are double variables and input values are 10.5 and 30.6. After the statement cin >> one >
SSSSS [86.1K]

Answer:

variable one stores 10.5 and two stores 30.6

Explanation:

In c++ language, the cout keyword is used to write to the standard output. The input from the user is taken by using the cin keyword.

For the input from the user, a variable need is declared first.

datatype variable_name;

The input can be taken one at a time as shown.

cin >> variable_name;

The input for more than one variable can be taken in a single line as given by the syntax below.

1. First, two variables are declared.

datatype variable_name1, variable_name2;

2. Both input is taken simultaneously as shown.

cin >> variable_name1, variable_name2;

For the given scenario, two double variables are declared as below.

double one, two;

The question mentions input values for the two double variables as 10.5 and 30.6.

3. The given scenario takes both the values as input at the same time, in a single line as shown below.

cin >> one >> two;

4. After this statement, both the values entered by the user are accepted.

The values should be separated by space.

First value is stored in the variable one.

Second value is stored in the variable two.

5. The user enters the values as follows.

10.5 30.6

6. The value 10.5 is stored in variable one.

7. The value 30.6 is stored in variable two.

The c++ program to implement the above is given below.

#include <iostream>

using namespace std;

int main() {

   double one, two;      

   cout << " Enter two decimal values " << endl;

   cin >> one >> two;

   cout << " The input values are " << endl;

   cout << " one : " << one << " \t " << " two : " << two << endl;

   return 0;

}

OUTPUT

Enter two decimal values  

10.5 30.6

The input values are  

one : 10    two : 530.6

6 0
3 years ago
What is the numerical ratio that is equivalent to 19.2 dB?
mrs_skeptik [129]

Answer: 83.17

Explanation:

By definition, the dB is an adimensional unit, used to simplify calculations when numbers are either too big or too small, specially in telecommunications.

It applies specifically to power, and it is defined as follows:

P (dB) = 10 log₁₀ P₁ / P₂

Usually P₂ is a reference, for instance, if P₂ = 1 mW, dB is called as dBm (dB referred to 1 mW), but it is always adimensional.

In our question, we know that we have a numerical ratio, that is expressed in dB as 19.2 dB.

Applying the dB definition, we can write the following:

10 log₁₀ X = 19.2 ⇒ log₁₀ X = 19.2 / 10 = 1.92

Solving the logarithmic equation, we can compute X as follows:

X = 10^1.92  = 83.17

X = 83.17

4 0
2 years ago
What is the next line?
jonny [76]

Answer:

Answered below

Explanation:

The next line is 1.

The python count function returns the number of times an element appears in a tuple or a list.

In the tupleB tuple, 7 is passed into the count function. The number of times 7 appears in tupleB is just once alongside 5, 2.7, 10 and 5. Therefore, the count function returns 1 in the next line.

5 0
2 years ago
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