Ask question

Ask question

All categories

notsponge [240]

3 years ago

11

Help me!!!

1 answer:

Basile [38]3 years ago

8 0

Answer:

this is your answer look it once.

You might be interested in

H(x-2)+6 In simpliest form

Ganezh [65]

Answer:

hx-h2+6

Step-by-step explanation:

First solve the parentheses, do h*x - 2h, then add the +6.

Hope I helped! :D

6 0

3 years ago

Please help me with this. 10 points! (Math)

Alex787 [66]

Felt appears to be right triangles

A appears to be an equilateral triangle

8 0

4 years ago

Read 2 more answers

Angle of 74° with the ground if the foot of the latter 6.5 feet from the wall, how high on the wall is the ladder?

Pie

Tanα=h/x

h=xtanα, we are told that x=6.5ft and α=74° so

h=6.5tan74 ft

h≈22.67 ft (to nearest hundredth of a foot)

7 0

3 years ago

I NEED HELP PLEASE, THANKS! :) Heather invests $4,900 in an account with a 3.5% interest rate, making no other deposits or withd

Alex

Answer: $5,828.28

<u>Step-by-step explanation:</u>

Use the Compound Interest formula: $A=P(1+\frac{r}{n})^{nt}$ where

A is the accrued amount (balance)
P is the principal (initial amount invested)
r is the interest rate (in decimal form)
n is the number of times compounded each year
t is the time of the investment (in years)

Given: P = 4,900

r = 3.5% (0.035)

n = 2

t = 5

$A=4,900\bigg(1+\dfrac{0.035}{2}\bigg)^{2(5)}\\\\\\.\qquad = 4900(1.0175)^{10}\\\\\\.\qquad = \large\boxed{5,828.28}\\$

5 0

3 years ago

Three consecutive odd integers have a sum of 27. Find the integers.

jek_recluse [69]

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

Sum of three consecutive odd integers = $27$

$\sf \bf {\boxed {\mathbb {TO\:FIND:}}}$

The values of the three integers.

$\sf \bf {\boxed {\mathbb {SOLUTION:}}}$

$\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}$

Let us assume the three consecutive odd integers to be $x$ , $(x+2)$ and $(x+4)$ .

As per the condition, we have

$Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27$

$➺ \: x + (x + 2) + (x + 4) = 27$

$➺ \: x + x + 2 + x + 4 = 27$

Now, collect the like terms.

$➺ \: (x + x + x) + (2 + 4) = 27$

$➺ \: 3x + 6 = 27$

$➺ \: 3x = 27 - 6$

$➺ \: 3x = 21$

$➺ \: x = \frac{21}{3} \\$

$➺ \: x = 7$

Therefore, the three consecutive odd integers whose sum is $27$ are $\boxed{ 7 }$ , $\boxed{ 9 }$ and $\boxed{ 11 }$ respectively.

$\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}$

$⇢ 7 + 9 + 11 = 27$

$⇢ 27 = 27$

⇢ L. H. S. = R. H. S.

$\sf\blue{Hence\:verified.}$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}$

4 0

3 years ago