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Vladimir79 [104]
3 years ago
12

Help me please. Thankyou :)​

Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0

Answer:

77 Sq m

Step-by-step explanation:

Area of the shaded shape = Area of the rectangle with dimensions 14 m by 8m - Area of rectangle with dimensions ( 14 - 5 - 2=7) 7m by 5m.

= 14*8 - 7*5

= 112 - 35

= 77 Sq m

Sliva [168]3 years ago
3 0

Answer:

The "area of the shaded shape" is 77 m^2.

Step-by-step explanation:

The white rectangle on the left of this figure has width 5 m and length (14 - 5 - 2) m, or 7 m.  <em>Check:  summing up the vertical side lengths on the left of this figure, we get (5 + 7 + 2) m = 14 m, which equals the unbroken 14 m on the right of this figure. </em>

Thus, the area of the white rectangle is 5 m times 7 m, or 35 m^2.

The area of the green rectangle, before the white one is cut out, is

8 m by 14 m, 112 m^2

Find the green area by subtracting the white area (35 m^2) from the uncut green area (112 m^2).  We get the net area (green area)

(112 m^2) - (35 m^2) = 77 m^2

The "area of the shaded shape" is 77 m^2.

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Answer:

D

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You started at level ground and then went deeper which represents the negatives. After you stick a five foot pole in there it sticks up 2 feet.

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Simplify using order of operations.Show all your work. 4^3 + (`10-8) divided by 2
Igoryamba

Answer:

<h2>65</h2>

Step-by-step explanation:

Use PEMDAS:

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E Exponents (ie Powers and Square Roots, etc.)

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------------------------------------------------------------------------

4^3+(10-8)\div2=64+2\div2=64+1=65

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what is the answer to Graph the function. f(x)=cos(x)−3 Use 3.14 for π i need it now im struggling on this test
kvv77 [185]

Answer:

we can draw the graph of cosine with amplitude 2.

Step-by-step explanation:

In the given function g(x) = 2cosx we know the following parameters which are helpful to draw the graph.

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2 years ago
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

7 0
3 years ago
Read 2 more answers
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