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Finger [1]
3 years ago
5

Which of the following factors put you at risk for injury?

Computers and Technology
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

1.Repetitive motions

2.Prolonged exposure to vibration

3. Long periods of localized pressure

Explanation:

Monica [59]3 years ago
4 0

Answer:

Prolonged exposure to vibration

Long periods of localized pressure

Explanation:

Repetitive motion is certainly not harmful, but prolonged repetitive motion can be a cause for injury. This is because if you are in repetitive motion for a long time, you exert a lot of force on your body, and that is certainly going to effect your body. And after a certain limit, even death can be a case. Hence, one should be very concerned about the time limit while their body goes through the repetitive motion.

However, neutral position we are always safe, as it’s an ideal position, as in this position, the work done is zero. Work done= force x displacement. And displacement in neutral position is zero. Hence, zero energy is lost. Hence, we are safe in this position.

Hence the above answer.

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Harrizon [31]

Answer:

The answer is "Option ".

Explanation:

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3 years ago
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Can someone please help me in answering this!?! <br> The language is C++
Llana [10]

Here is a somewhat cryptic solution that works:

#include <algorithm>

#include <cstdlib>

using namespace std;

void q(char c, int count)

{

for (int i = 0; i < count; i++) {

 putchar(c);

}

}

void p(int b1, int plusses)

{

q(' ', b1);

q('+', plusses);

}

int main()

{

for (int i = -3; i <= 3; i++)

{

 int pl = min(6, (3 - abs(i)) * 2 + 1);

 p(6-pl, pl);

 i == 0 ? p(0, 6) : p(6, 0);

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5 0
3 years ago
Public class SomeClass { private String aName; private int aNumber; private boolean amAwesome; public SomeClass(String name, int
scoray [572]

Answer:

The objects created in the main method and their initial states are given below

Explanation:

The objects and initial state of each object( the values of each object’s variables) are thus:

We have objects awesome, amazing and fantastic.

initial state of awesome object is

aName = "Awesome"; aNumber = 5; amAwesome = true;

initial state of amazing object is

aName = "Amazing"; aNumber = -10; amAwesome = false;

initial state of fantastic object is

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3 0
3 years ago
Earning wise scope of web and mobile app development
lubasha [3.4K]

Answer:

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Explanation:

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3 years ago
An IT systems engineer creates a new Domain Name System (DNS) zone that contains a pointer (PTR) resource records. Which zone ty
irina1246 [14]

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