PLZ HELP ME THANKS! I'll mark brainliest as well.
1 answer:
Answer:
Keiko will have 200 subscribers first.
Step-by-step explanation:
Function describing the relation between the number of subscribers and number of months for Keiko is,
K = m² + 10
Where K = Number of subscribers
m = Number of months
If the number of subscribers are K = 200,
200 = m² + 10
m² = 200 - 10
m = √190
= 13.78
≈ 13.8 months
Relation between subscribers and number of months for Jayden is given by the table attached.
Let the function is,
K = mx + b
Where K = number of subscribers
m = slope of the function
x = number of months
b = y-intercept
Slope of the linear function (from the table attached) is,
m =
= 8
y-intercept 'b' = Value of the function at x = 0
= 48
Therefore, function will be,
K = 8x + 48
200 = 8x + 48
8x = 200 - 48
x = 19 months
Therefore, Keiko will have 200 subscribers first.
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Answer:
Step-by-step explanation:
In leftmost triangle:
opposite side =y
adjacent=a
now, we can use trig formula
now, we can solve for y
In rightmost triangle:
adjacent=b
opposite=y
a+b=15
b=15-a
now, we can use trig formula
now, we can solve for y
now, we can set them equal
and then we can solve for a
now, we can find b
now, we can use trig formula
now, we can find z
we can simplify it
and we get
We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral
This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000