The answer is 5
Here are the steps:
First off, we will be using the distance formula of
![d=\sqrt{(x_ {2}- x_{2}) ^{2}+( y_{2}- y_{1})^2 }](https://tex.z-dn.net/?f=%20d%3D%5Csqrt%7B%28x_%20%7B2%7D-%20x_%7B2%7D%29%20%5E%7B2%7D%2B%28%20y_%7B2%7D-%20y_%7B1%7D%29%5E2%20%20%20%20%20%7D%20)
So we have the ordered pairs of (3,1) and (6,5)
Once you plug them into the formula it should look like this:
![d= \sqrt{(6-3)^2+(5-1)^2}](https://tex.z-dn.net/?f=d%3D%20%5Csqrt%7B%286-3%29%5E2%2B%285-1%29%5E2%7D%20)
Now we do the math inside the parenthesis and end up with:
![d=\sqrt{3^2+4^2}](https://tex.z-dn.net/?f=%20d%3D%5Csqrt%7B3%5E2%2B4%5E2%7D%20)
Then you multiply by the power and simplify to get:
![d=\sqrt{25}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B25%7D%20)
And the
![\sqrt{25}](https://tex.z-dn.net/?f=%20%5Csqrt%7B25%7D%20)
=5
So your answer is
5
Let XXX and YYY be the following sets: X = \{9, 25\}X={9,25}X, equals, left brace, 9, comma, 25, right brace Y = \{1, 4, 9,16,25
Dmitry_Shevchenko [17]
Answer:
The answer is "
"
Step-by-step explanation:
Given value:
![\ Set\ X = \{9, 25\} \\\\\ Set \ Y = \{ 1,4,9,16,25 \}\\\\Find: \\\\Set (X- Y) \\\\](https://tex.z-dn.net/?f=%5C%20Set%5C%20X%20%20%3D%20%5C%7B9%2C%2025%5C%7D%20%5C%5C%5C%5C%5C%20Set%20%5C%20Y%20%3D%20%5C%7B%201%2C4%2C9%2C16%2C25%20%5C%7D%5C%5C%5C%5CFind%3A%20%5C%5C%5C%5CSet%20%28X-%20Y%29%20%5C%5C%5C%5C)
When we subtract set X - Y it means, that it will give only, that value which is not available on the set Y.
![\{X-Y\} = \{\phi\}](https://tex.z-dn.net/?f=%5C%7BX-Y%5C%7D%20%3D%20%5C%7B%5Cphi%5C%7D)
3^4 + 2 * 5 = 91
The answer is 91.
Answer:
Step-by-step explanation:
congruent angles:
angle A = H
B = J
K = C
L = D
proportional side :
AB proportional HJ
AD proportional HL
JK proportional BC
KL proportional CD
hope it helps
if it does so then please mark me as brainliest