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3 years ago

3 1/4 divided by 1 1/4 =

2 answers:

6 0

Change to improper fractions
13/4 5/4
keep the first fraction the same
Change sign to multiply
Flip second fraction
13/4 x 4/5 = 52/20
change back to mixed fraction
2 12/20

Vladimir [108]3 years ago

4 0

Answer:

2.6, 2 3/5, 2 6/10

Step-by-step explanation:

2.6 as a fraction is 2 3/5. When you read the decimal 2.6, it is read as ''2 and 6 tenths. '' This can also be written as a mixed number of 2 6/10.

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At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acce

Bad White [126]

Answer:

Let v(t) be the velocity of the car t hours after 2:00 PM. Then $\frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }$ . By the Mean Value Theorem, there is a number c such that $0 < c$ with $v'(c)=60 \:{\frac{mi}{h^2}}$ . Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly $60 \:{\frac{mi}{h^2}}$ .

Step-by-step explanation:

The Mean Value Theorem says,

Let be a function that satisfies the following hypotheses:

f is continuous on the closed interval [a, b].
f is differentiable on the open interval (a, b).

Then there is a number c in (a, b) such that

$f'(c)=\frac{f(b)-f(a)}{b-a}$

Note that the Mean Value Theorem doesn’t tell us what c is. It only tells us that there is at least one number c that will satisfy the conclusion of the theorem.

By assumption, the car’s speed is continuous and differentiable everywhere. This means we can apply the Mean Value Theorem.

Let v(t) be the velocity of the car t hours after 2:00 PM. Then $v(0 \:h) = 30 \:{\frac{mi}{h} }$ and $v( \frac{1}{3} \:h) = 50 \:{\frac{mi}{h} }$ (note that 20 minutes is $20/60=1/3$ of an hour), so the average rate of change of v on the interval $[0 \:h, \frac{1}{3} \:h]$ is

$\frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }$

We know that acceleration is the derivative of speed. So, by the Mean Value Theorem, there is a time c in $(0 \:h, \frac{1}{3} \:h)$ at which $v'(c)=60 \:{\frac{mi}{h^2}}$ .

c is a time time between 2:00 and 2:20 at which the acceleration is $60 \:{\frac{mi}{h^2}}$ .

4 0

3 years ago

In the diagram, line segment CD is the perpendicular bisector of line segment AB, and E is a point not on either line that is on

Lelu [443]

Answer:

E would be closer to A

explanation:

if they were the same distance from both A and E it would be a point on the line CD, and if it was closer to E it would be on the other side of line CD.

i hope this is right :/

4 0

2 years ago

The art club held a car wash on Saturday and Sunday. They washed a total of 50 cars. If they washed 30% of the cars on Sunday, h

o-na [289]

Answer:

If I did my math correctly, They washed 15 cars on Sunday.

Step-by-step explanation:

50 cars = 100%

Therefore 1 car would be 2% because 50 is half of 100.

So because 30% would be 2 times the amount of cars, we divide 30 by 2, giving us 30% = <u>15 cars on Sunday</u>

With this information, we can take away 15 from 50 giving us 35 cars which is equal to 70% on Saturday

Here is some extra data:

10% = 5 cars

20% = 10 cars

30% = 15 cars

40% = 20 cars

50% = 25 cars

60% = 30 cars

70% = 35 cars

80% = 40 cars

90% = 45 cars

100% = 50%

Basically, every 10% is +5 cars

6 0

2 years ago

Solving systems of equations by substitution<br> Y=6x y=5x+7

soldi70 [24.7K]

Y=6x (1)
y=5x-7 (2)

Substitute y into (2)
(6x)=5x-7 -- subtract 5x from both sides
x=-7

Sub x into 1
y=6(-7)
y=-42

x=-7
y=-42

8 0

3 years ago

Read 2 more answers

What is the phase shift of the graph of y=−sin(x+π/4)+2

butalik [34]

Answer:

π/4

Step-by-step explanation:

x is the variable

-1 inverts the curve

π/4 is the phase shift or x axis offset

2 is the y axis offset

5 0

2 years ago