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3 years ago

3 1/4 divided by 1 1/4 =

2 answers:

6 0

Change to improper fractions
13/4 5/4
keep the first fraction the same
Change sign to multiply
Flip second fraction
13/4 x 4/5 = 52/20
change back to mixed fraction
2 12/20

Vladimir [108]3 years ago

4 0

Answer:

2.6, 2 3/5, 2 6/10

Step-by-step explanation:

2.6 as a fraction is 2 3/5. When you read the decimal 2.6, it is read as ''2 and 6 tenths. '' This can also be written as a mixed number of 2 6/10.

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when adding two rational numbers tell what the sign of the sum will be if one rational number is positive and one is negative

Mekhanik [1.2K]

Answer:

True

When you add two negative numbers the sum is always negative ex.

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Step-by-step explanation:

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2 years ago

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Anarel [89]

Answer:

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3 years ago

A line passes through the point (0-1) and has a positive slope. Which of these points could that line pass through?

juin [17]

Answer:

(12,3) A

(-2,-5) B

(1,15) D

Step-by-step explanation:

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3 years ago

Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.

Nuetrik [128]

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

$(x-r_{i})^{m},\,m \le n$ (1)

Where $n$ is the grade of the polynomial.

Now we proceed to factor the formula:

$y = x^{5}-27\cdot x^{2}$

$y = x^{2}\cdot (x^{3}-27)$

$y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)$

Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

$y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3} \right)\cdot (x-3)$

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

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3 years ago

Use the quadratic formula to find both solutions to the quadratic equation

astraxan [27]

Answer:

A and B are correct

Step-by-step explanation:

8 0

2 years ago