So first step is to simplify everything outside of the radicals.
6*2=12
:. The expression is
__ __
12*\| 8 * \| 2
Now we know that
__ __ __
\| 8 = \| 4 * \| 2
And
__ __
\| 2 * \| 2 = 2
And
__
\| 4 = 2
So if we incorporate what we know into the equation, we can figure it out.
So let's first expand the radical 8.
__ __ __
12*\| 4 * \| 2 * \| 2
Now by simplifying the radical four and combining the radical twos, we can get all whole numbers.
12*2*2
Which equals 48.
Answer:48
Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
it is 1
Step-by-step explanation:
Swap the n with the 7
7-5
Find the answer to 7-5
7-5=2
So the answer is 2
Answer:
B) [1, 4, 7]
Step-by-step explanation:
Substitute 0 in
f(0) = 3(0) + 1
Multiple
f(0) = 0 + 1
f(0) = 1
Substitute 1 in
f(1) = 3(1) + 1
f(1) = 3 + 1
f(1) = 4
Substitute 2 in
f(2) = 3(2) + 1
2 = 6 + 1
f(2) = 7
