Answer:
1872
Step-by-step explanation:on edge
Answer:
{3¢, 28¢} or {4¢, 19¢} or {7¢, 10¢}
Step-by-step explanation:
54 = 1×54 = 2×27 = 3×18 = 6×9
Possible values of the stamps are 1 more than the values of a pair of factors. Of course, a 2¢ and 55¢ stamp will not permit paying 54¢ in postage, so that combination won't work. However, other pairs that will work are ...
- 3¢ and 28¢
- 4¢ and 19¢
- 7¢ and 10¢
Ok so assuming the board only has 4 spaces to land on (A,B,C,D) all we need to do is weight the probability,
1/4 x 1/4 x 1/4 x 1/4 x 1/4 = 1/1024
To solve I put the number of favorable outcomes over the number of total outcomes, in this case we had 1 favorable outcome each time and a constant of 4 possible outcomes.
X to the one third power plus x to the 2/3 power= 3
Volume of a cone: 1/3*pi*4*4*5 = 83.776 cubic cm rounded up to 3 decimal places