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3 years ago

HELP PLEASE I WILL GIVE YOU THE BRAINLIEST

Mathematics

1 answer:

ira [324]3 years ago

4 0

Answer:

volume = area of its × its height

v= 2×3.5×4×1

v=28 meter cube

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_____ is the current illustration used to show us how to eat a healthy diet. Basic Four Basic Four My Plate My Plate Food Pyrami

Serhud [2]

Answer:

My Plate.

<em>My Plate</em> is the current illustration used to show us how to eat a healthy diet.

Here is the My Plate diagram.

<em>I hope this helped at all.</em>

5 0

3 years ago

Please help I'll give brainliest

SIZIF [17.4K]

Answer:

y + 1 = 4(x - 2)

y = 4x + 11

8x - 2y = 6

Step-by-step explanation:

Following equations are parallel to the graph 4x - y = 6, because their slopes are equal (4).

y + 1 = 4(x - 2)

y = 4x + 11

8x - 2y = 6

8 0

3 years ago

What is the interquartile range of the box and whisker plot

Irina18 [472]

Answer:

(IQR) interquartile range = 5

Step-by-step explanation:

Lower quartile: 48

Upper quartile: 53

Median: 52

Lowest value: 46

Highest value: 55

(IQR) interquartile range: Upper quartile - Lower quartile = final answer

(IQR) interquartile range: 53 - 48 = 5

5 0

3 years ago

What is the solution set to, "Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each da

Anastaziya [24]

Answer:

Katie will collect more than 100 seashells in 5 and a half days.

Step-by-step explanation:

Katie already has 34 seashells in her collection.

Each day, she finds 12 more seashells on the beach.

Let x be the number of days Katie is collecting seashells.

In x days, she will collect 12x seashells.

In total, she will collect $34+12x$ seashells.

Katie wants to collect over 100 seashells, so

$34+12x> 100$

Solve this inequality. Subtract 34:

$34+12x-34>100-34\\ \\12x>66\\ \\2x>11\\ \\x>5 \dfrac{1}{2}$

Katie will collect more than 100 seashells in 5 and a half days.

3 0

3 years ago

Suppose that we have a sample space S5 {E1, E2, E3, E4E4E, E5, E6, E7}, where E1, E2, . . ., E7 denote the sample points. The fo

VashaNatasha [74]

Answer:

P(A) = 0.4 ; P(B) = 0.50 ; P(C) = 0.60 ; P(A u B) = 0.65 ; P(A n B) = 0.25 ;

A and C are mutually exclusive ;

0.5

Step-by-step explanation:

S = {E1, E2, E3, E4, E5, E6, E7}

P(E1) = .05, P(E2) = .20, P(E3) = .20, P(E4) = .25, P(E5) = .15, P(E6) = .10, and P(E7) = .05

Let:

A{E1,E4,E6}

B{E2,E4,E7}

C{E2,E3,E5,E7}

P(A) = 0.05 + 0.25 + 0.10 = 0.40

P(B) = 0.20 + 0.25 + 0.05 = 0.50

P(C) = 0.20 + 0.20 + 0.15 + 0.05 = 0.60

AUB = {E1, E2, E4, E6, E7}

P(A u B) = 0.05 + 0.20 + 0.25 + 0.10 + 0.05 = 0.65

AnB = {E4}

P(A n B) = 0.25

A and C are mutually exclusive if AnC = ∅

A n C = ∅

Hence, A and C are mutually exclusive.

B complement = B' = {E1, E3, E5, E6}

P(B') = 0.05 + 0.20 + 0.15 + 0.10 = 0.5

5 0

3 years ago