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dedylja [7]
3 years ago
15

5x-9>4 and sketch a graph on that question​

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

Step-by-step explanation:

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The Kirkland family is buying a new living room set that costs $1,495.
never [62]
<h3>Answer:   173.04 dollars</h3>

======================================================

Explanation:

The down payment is $400, so that means they must pay back 1495-400 = 1095 dollars. Let L = 1095 be the amount loaned

The annual interest rate is 28% which means r = 0.28; the monthly interest rate is i = r/12 = 0.28/12 = 0.02333 approximately

There are 12 months in a year, so n = 12 is the number of payment periods

----------------------------------------

In summary so far, we have

  • L = 1095
  • i = 0.02333 (which is approximate)
  • n = 12

Those values will be plugged into the monthly payment formula below

M = L*( i*(1+i)^n )/( (1+i)^n - 1 )

M = 1095*( 0.02333*(1+0.02333)^12 )/( (1+0.02333)^12 - 1 )

M = 105.671914631108

M = 105.67

The monthly payment is $105.67

If they have a monthly payment of $105.67, and they pay that for 12 months, then 12*105.67 = 1,268.04 dollars is the amount of money they pay back to the credit card company.

The total amount of interest would be 1,268.04 - 1,095 = 173.04 dollars

Side note: the formula is a complicated ugly mess, so it's understandable to use calculators that already have the formula built in. Many websites offer free calculators that do this.

7 0
3 years ago
jet skis rent for $25 per hour plus a flat fee of $50. Noel can rent the jet ski for 6 hours. what is the largest value in the r
telo118 [61]

Answer:

The largest value in this situation would be $25+$50x6 which equals $450

5 0
3 years ago
Read 2 more answers
A model for the population in a small community after t years is given by P(t)=P0e^kt.
LUCKY_DIMON [66]
\bf \textit{Amount of Population Growth}\\\\&#10;A=Ie^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;t=\textit{elapsed time}\\&#10;\end{cases}

a)

so, if the population doubled in 5 years, that means t = 5.  So say, if we use an amount for "i" or P in your case, to be 1, then after 5 years it'd be 2, and thus i = 1 and A = 2, let's find "r" or "k" in your equation.

\bf \textit{Amount of Population Growth}\\\\&#10;A=Ie^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &2\\&#10;I=\textit{initial amount}\to &1\\&#10;r=rate\\&#10;t=\textit{elapsed time}\to &5\\&#10;\end{cases}&#10;\\\\\\&#10;2=1\cdot e^{5r}\implies 2=e^{5r}\implies ln(2)=ln(e^{5r})\implies ln(2)=5r&#10;\\\\\\&#10;\boxed{\cfrac{ln(2)}{5}=r}\qquad therefore\qquad \boxed{A=e^{\frac{ln(2)}{5}\cdot t}} \\\\\\&#10;\textit{how long to tripling?}\quad &#10;\begin{cases}&#10;A=3\\&#10;I=1&#10;\end{cases}\implies 3=1\cdot e^{\frac{ln(2)}{5}\cdot t}

\bf 3=e^{\frac{ln(2)}{5}\cdot t}\implies ln(3)=ln\left( e^{\frac{ln(2)}{5}\cdot t} \right)\implies ln(3)=\cfrac{ln(2)}{5} t&#10;\\\\\\&#10;\cfrac{5ln(3)}{ln(2)}=t\implies 7.9\approx t

b)

A = 10,000, t = 3

\bf \begin{cases}&#10;A=10000\\&#10;t=3&#10;\end{cases}\implies 10000=Ie^{\frac{ln(2)}{5}\cdot 3}\implies \cfrac{10000}{e^{\frac{3ln(2)}{5}}}=I&#10;\\\\\\&#10;6597.53955 \approx I
3 0
3 years ago
I will give brainliest to first (2x^2 − 7x^3 + 8x) + (−8x^3 − 3x^2 + 4)
cluponka [151]

Answer:-15x^3-x^2+8x+4

Sry if I am wrong

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
In a music competition, a participant has to score a total of at least 40 points in the first four rounds combined to move on to
MAXImum [283]
4+3p≥40
He needs to have 40 or more to get to the finals so 4+3p has to be 40 or more
7 0
3 years ago
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