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11111nata11111 [884]

3 years ago

8

A textbook store sold a combined total of 294 physics and psychology textbooks in a week. The number of psychology textbooks sol

d
was 42 less than the number of physics textbooks sold. How many textbooks of each type were sold?

1 answer:

miv72 [106K]3 years ago

5 0

Answer:

105 psychology textbooks. 189 physics textbooks.

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7. G(2, 2), H(3, -1), J(-2, -1),

kramer

Answer:

So , do you need to see how that is graphed?

Step-by-step explanation:

5 0

3 years ago

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is $\overline A=\textrm{Missing a target at least once}$

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, $P(A)=0.95^{10}=0.5987$

We know that the sum of probability of an event and its complement is 1.

So, $P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%$

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

6 0

3 years ago

Read 2 more answers

Find the 55th term in the following<br> arithmetic sequence :<br> -102, -98, -94, -90, ...

Harman [31]

Answer: It’s...

Step-by-step explanation: All of these numbers are going backwards by -4. Just keep subtracting. But then again, it will take you ages. So... try multiplying 51 by -4. Then -86 - whatever total you got. I have no clue if this will help. Is this even an assignment for you or a trick question?

4 0

3 years ago

An animal shelter recently held an adoption event and found homes for 48 of their shelter animals. If they found home for 80% of

Elden [556K]

There were 60 animals before the event.

5 0

3 years ago

A card is picked from a standard deck of 52 cards. Determine the odds against and the odds in favor of selecting a red face card

timama [110]

<h3>The probability of picking a red face card from the deck is $(\frac{3}{26} )$ </h3><h3>The probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$ </h3>

Step-by-step explanation:

The total number of cards in the deck = 52

The total number of red( Diamond + Hearts) face cards in the given deck

= 2 Red Queens + 2 Red jacks + 2 Red kings = 6 cards

Let E : Event of picking a red face card from the deck

Now , P( any event) = $\frac{\textrm{The number of favorable observations}}{\textrm{Total number of observations}}$

So, here P(Picking a red face card) = $\frac{\textrm{The number of red face cards}}{\textrm{Total number of cards}} = (\frac{6}{52} ) = (\frac{3}{26})$

Hence, the probability of picking a red face card from the deck is $(\frac{3}{26} )$

Now, as we know P (any event NOT A) = 1 - P(any event A)

So, P(NOT Picking a red face card) = 1 - P(Picking a red face card)

$= 1 - (\frac{3}{26} ) = \frac{26-3}{26} = (\frac{23}{26})$

Hence, the probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$

8 0

3 years ago