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3 years ago

I am thinking of a number.... When I divide my number by 2 and add 1, I get 13. What is my number?

Mathematics

2 answers:

dedylja [7]3 years ago

8 0

Answer:

Dude go to photomath

Step-by-step explanation:

It's easy

wariber [46]3 years ago

7 0

Answer:

Step-by-step explanation:

24 divided by 2 is 12, adding 1 to 12 would get 13. Hope this helped!!

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Determine if the two triangles are congruent.

goldenfox [79]

Answer:

Yes

Step-by-step explanation:

Since they have 3 identical sides, they are congruent by SSS congruence.

HTH :)

6 0

2 years ago

Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?

serious [3.7K]

Answer:

c) 6x + y = -52 is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form : y = mx + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 : -x + 6y = -12

or, 6y = -12 + x

or, y = (x/6) - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2 to be perpendicular:

Check for each equation:

a. x + 6y = -67 ⇒ 6y = -67 - x

or, y = (-x/6) - (67/6) ⇒Slope of line 2 = (-1/6)

but $\frac{1}{6} \times \frac{-1}{6} \neq -1$

b. x - 6y = -52 ⇒ -6y = -52 - x

or, y = (x/6) + (52/6) ⇒Slope of line 2 = (1/6)

but $\frac{1}{6} \times \frac{1}{6} \neq -1$

c. 6x + y = -52

or, y =y = -52 - 6x ⇒Slope of line 2 = (-6)

$\frac{1}{6} \times (-6) = -1$

Hence, 6x + y = -52 is required equation 2.

d. 6x - y = 52 ⇒ -y = 52 - 6x

or, y = 6x - 52 ⇒Slope of line 2 = (6)

but $\frac{1}{6} \times 6 \neq -1$

Hence, 6x + y = -52 is the only required equation .

3 0

3 years ago

Read 2 more answers

Help me please will be appreciated thx

alexandr1967 [171]

Answer:

-6 +8d -2c

Step-by-step explanation:

$\frac{-2}{5} (15 -20d +5c) = \frac{-2}{5} \times 15 - \frac{-2}{5}\times20d +\frac{-2}{5}\times5c = -6 + 8d -2c$

3 0

2 years ago

Wasn’t sure how to write this out : - )

amid [387]

we are given

$\frac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}$

we can write it in terms of exponents

$\frac{7^{\frac{1}{3}}*7^{\frac{1}{2}}}{7^{\frac{5}{6}}}$

Firstly , we will simplify numerator

$\frac{7^{\frac{1}{3}+\frac{1}{2}}}{7^{\frac{5}{6}}}$

now, we can add exponents

$\frac{7^{\frac{5}{6}}}{7^{\frac{5}{6}}}$

we can cancel it

and we get

$=1$ ............Answer

5 0

3 years ago

Use binomial theorem to expand (2+X)5 in ascending powers of x up to the terms containing x3 and Use your expansion to find (1.

TEA [102]

Answer:

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Brown bears dig dens for winter hibernation, often holing up in a suitable-looking hillside. Females give birth during this winter rest, often to twins.

Grizzly bears are powerful, top-of-the-food-chain predators, yet much of their diet consists of nuts, berries, fruit, leaves, and roots. Bears also eat other animals, from rodents to moose.

Despite their impressive size, grizzlies have been clocked running at 30 miles an hour. They can be dangerous to humans, particularly if surprised or if humans come between a mother and her cubs.

Habitat

Grizzlies once lived in much of western North America and even roamed the Great Plains. These animals need a lot of space—their home range can encompass up to 600 square miles—so their ideal habitat is one that is isolated from development and has plenty of food and places to dig their dens.

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5 0

3 years ago