2 years ago

3x = 8 3x + y = 15 ???

1 answer:

6 0

3x=8

Solve for x by dividing by 3 on both sides

x=8/3

Now plug 8/3 in for x in second equation

3(8/3)+y=15

This gives you

8+y=15

Subtract by 8 on both sides to find y

y=8

Now write it in ordered pair form (x,y)

So your answer is (8/3,8)

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PLEASSS HELP!!!!!!! I REALLY NEED HELP!!

loris [4]

Answer:

$\underline{ \boxed{x = 11} } \\ \underline{ \boxed{ABE = 55}}$

Step-by-step explanation:

$if \: the \: question \: is \to \\ \overline{AZ} \: \perp \: \overline{CD}, \: m \angle{ABE} = 5x, \\ and \\ \: m \angle{EBD } = 3x + 2\\ but \: m \angle{EBD } + m \angle{ABE} = 90 \\ hence \to \\ (3x + 2) + (5x) = 90 \\ 8x + 2 = 90 \\ 8x = 90 - 2 \\ 8x = 88 \\ x = \frac{88}{8} \\ \boxed{ x = 11} \\ \\ if \: x = 11, \: then \to \\ m \angle{ABE} = \: 5x = 5(11) \\ \boxed{m\angle{ABE} =55}$