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3 years ago

What is the slope of the line?

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

7 0

Answer:

2/1

Step-by-step explanation:

Slope can be found by using rise/run

in other words count the number of spots rising up then move to either left or right (up and to the right in this case)

yes the slope could be -2/1 from a reflective point. Rise/Run pov or positive pov it's 2/1

vlada-n [284]3 years ago

6 0

Answer:

the slope is 2

Step-by-step explanation:

it crosses the point (-2, -4), which from there to the next crossing coordinate (-1, -2), it goes up +2 units on the y-axis and goes to the right on the x-axis +1 units

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Suppose that the populations of the United States and China both increase by 12 million people in one year. What would be the re

Jlenok [28]

Question:

Suppose that the populations of the United States and China both increase by 12 million people in one year. What would be the relative change for each country? Answer to the nearest tenth of a percent (1 decimal place). Make sure that you fill in each answer area before checking "How Did I Do?".

If you assume that the U.S. population is about 300 million, an increase of 12 million would result in a relative change of Number %.

If you assume that China has about 1 billion people, an increase of 12 million would result in a relative change of Number %.

Answer:

The relative change of the United States and China is 4% and 1.2%, respectively.

Step-by-step explanation:

Given

Represent population with p. So, we have:

United States

$\triangle p = 12\ million$

$p_1 =300\ million$

China

$\triangle p = 12\ million$

$p_1 =1\ billion$

Required

Determine the relative change for each country

Relative change, C is calculated as:

$C = \frac{\triangle p}{p} * 100\%$

For United States

$C = \frac{12\ million}{300\ million} * 100\%$

$C = \frac{12}{300} * 100\%$

$C = \frac{12 * 100}{300}\%$

$C = \frac{1200}{300}\%$

$C = 4\%$

For China

$C = \frac{12\ million}{1\ billion} * 100\%$

$C = \frac{12}{1000} * 100\%$

$C = \frac{12* 100}{1000} \%$

$C = \frac{1200}{1000} \%$

$C = 1.2\%$

The relative change of the United States and China is 4% and 1.2%, respectively.

3 0

2 years ago

Which of the following scenarios is least likely to be modeled by a quadratic function?

vampirchik [111]

I think the answer is c purplestar1

8 0

3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

In the figure, ∠1 ≅ ∠2, ∠3 ≅ ∠4, and . You can justify the conclusion that ∠TKL ≅ ∠TLK by stating _____

VladimirAG [237]

From the question, we know that we will be looking at <3, <4, and angles TKL and TLK. That being said, since <3 is congruent to <4, that means that angles TKL and TLK, which are each supplementary to either angle 3 or 4, are congruent because, since angles 3 and 4 are congruent, they are congruent because the supplements of congruent angles are congruent.

3 0

2 years ago

Read 2 more answers

What is the coefficient of the y-term in the expression 4x 5xy–2y

Bad White [126]

In 5xy it would be 5x×1y and then 2y if they variable doesn't have a number infront of it it is assumed to be a One.

3 0

3 years ago