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belka [17]
3 years ago
9

What is the slope of the line?

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
7 0

Answer:

2/1

Step-by-step explanation:

Slope can be found by using rise/run

in other words count the number of spots rising up then move to either left or right (up and to the right in this case)

yes the slope could be -2/1 from a reflective point. Rise/Run pov or positive pov it's 2/1

vlada-n [284]3 years ago
6 0

Answer:

the slope is 2

Step-by-step explanation:

it crosses the point (-2, -4), which from there to the next crossing coordinate (-1, -2), it goes up +2 units on the y-axis and goes to the right on the x-axis +1 units

You might be interested in
A florist needs several pieces of ribbon that are 5 and 1/2 inches long if she begins with a piece of ribbon that is 264 inches
dimaraw [331]

Answer:

  48

Step-by-step explanation:

(264 in)/(5.5 in/piece) = (264/5.5) pieces = 48 pieces

_____

Division is the usual shortcut for repeated subtraction. You could subtract 5.5 from 264 until you get to zero. You would have to do 48 subtractions. It is easier to divide 264 by 5.5 to see how many times it goes.

8 0
3 years ago
Number 14 please thanks
katrin [286]
Your problem is:
$35.00 is what percentage of $437.50?

If you are given a part and the whole, and you want to know what percent the part is of the whole, divide the part by the whole and multiply by 100.

In this case, the whole is $437.50.
The part is $35.00.

35/437.5 * 100 = 8%

3 0
2 years ago
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
3 years ago
Find the area of this polygon - PLZZZZZ HELP I WILL GIVE 30 points T^T
balu736 [363]

Answer:

82 m should be correct i hope

Step-by-step explanation:

5 0
2 years ago
Evaluate the function y= -3 (1/4) for x =-3 on top of the 1/4 is where the x goes. so it is 1/4 x
earnstyle [38]

\text{Consider the function}\\
\\
y=-3\left ( \frac{1}{4} \right )^x\\
\\
\text{now to evaluate the value of the function at }x=-3, \text{ we substitute}\\
x=-3 \text{ in the given function and solve further for y.}\\
\\
\text{so we get}\\
\\
y=-3\left ( \frac{1}{4} \right )^{-3}\\
\\
\text{now using the exponent property, }\left ( \frac{1}{a} \right )^{-m}=(a)^m, \text{ we get}\\
\\
y=-3(4)^{3}\\
\\
\Rightarrow y=-3(64)\\
\\
\Rightarrow y=-192

so the value of the function at x=-3 is -192

7 0
3 years ago
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